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Systematische Natuurkunde VWO 5 Uitwerkingen Bovenbouw hoofdstuk 10
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Antwoorden Systematische natuurkunde hoofdstuk 10 Elektromagnetisme V5
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Vwo 5 Hoofdstuk 10 Uitwerkingen CONCEPT10.1 Elektrische velden
Opgave 1
a De elektrische kracht bereken je met de wet van Coulomb.
q Q
Fel f
r2
8 2 −2
f = 8,987∙10 N m C
q = 1,0 C
Q = 1,0 C
r = 80 cm = 0,80 m (Afstemmen eenheden)
1,0 1,0
Fel 8,987 10 9
0,802
10
Fel = 1,404∙10 N
10
Afgerond: Fel = 1,4∙10 N
b Hoeveel keer de elektrische kracht groter is dan de gravitatiekracht, bereken je met de
verhouding tussen de elektrische kracht en de gravitatiekracht.
De gravitatiekracht tussen de bollen bereken je met de formules voor de
gravitatiekracht.
mM
Fg G
r2
−11 2 −2
G = 6,673∙10 N m kg
m = 0,59 kg
M = 0,59 kg
r = 80 cm = 0,80 m
0,59 0,59
Fg 6,673 1011
0,802
−11
Fg = 3,629∙10 N
1,404 1010 20
De elektrische kracht 3,868∙10 keer zo groot.
3,629 1011
20
Afgerond: 3,9∙10
Opgave 2
a De elektrische veldsterkte bereken je met de formule voor de elektrische veldkracht.
Fel = q ∙ E
-16
Fel = 8,0∙10 N
-19
q = +1e = 1,602∙10 C
−16 −19
8,0∙10 = 1,602∙10 E
E = 4993 N/C
Afgerond = 5,0 kN/C
b De kracht is even groot, omdat het elektrische veld tussen twee condensatorplaten
homogeen is.
c De versnelling volgt uit de tweede wet van Newton.
Fres = m · a
2+
De lading van het Pb -ion is twee keer zo groot, dus de elektrische kracht is 2,0 keer
zo groot.
2+ +
De massa van het Pb -ion is 207,2 u en de massa van het Na -ion is 22,99 u.
De massa van het lood-ion is dus meer dan twee keer zo groot als de massa van het
+
Na -ion.
De versnelling is dus kleiner.
© ThiemeMeulenhoff bv Pagina 1 van 24
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