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Summary AQA A Level Physics revision poster - ELECTRICITY
- Vak
- Instelling
colourful poster that includes all of the content for aqa a level physics, electricity module. brief but contains all information to aid revision.
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Voorbeeld van de inhoud
In characteristicscurrent-rate of fow it charge
-
I = 11 -circuit used to investigate the current and
I
positive lo regative in conventional current
Power
A -
Pd g tre resistor using a variable resistor
-
flows from
-
P= PR
P IV , P VYR
=
=
between
potential difference
, -
-
The current exises because or a
one end and the other Power is the (P= e/t) ... = IVT I -
A piece es metal at a constant
temperative
rate of energy transfer
potential difference -
w
-
-
A resistor
(voctage) Q try onnic conductor (ebep onn's
raw)
Potential dividers
per charge
te mount o energy transferred
-
carrier
911
-
using te relative size e He resistere in (I & V provided there are constant physical conditions)
resistor spect the pd
each we ca ther
↑
-
a
bigger pal a
bigger wiret
-
~
#*
divided
difference component,
I RI
resistance ratio of potential across the -
An example of a
potential divider circuit R however ,
Ohm's law - =
by grad
the cur re in the component is en external change a
chage the internal
I
-
resistance x
#
-
filement bui
e .
9
A
- (LDR) M resistence point
>
at
-
=
-
~ eny
E
excromotive force -E >v
&
=
,
(emf)
-
energy pasferred to
e g by battery
the circuit
A
y
. a
I
diode
↑
-
- -
current direction
only flows is I
electricity
&
Resistivity
Re conductors
+
>v
If
you have wire with certain resistere it depenses
Cicuits
a a
↳
be its legen
X
↓
.
e
. if charge is conserved
-
g you double the
length you double resistance
.
the
because where ↑
is more to slow down the cverge carriers Ii= I out & Kirchoff's 1st
However
If you increase the crea
juncra
,
the resistance law
as seeire is thicker and
,
there is
decreases : Elin
=
Elout ir a
more
space for te charge
carriers to How through Internal Resistance energy is also
conserved
resistivity things line I
↑
Internal resistance
A
am can corre from closed circuit
p
=
in in a
resistance crenicals a
battery ,
EE SV
911
=
crece
m2 resister
x nor an annual
---
~R
egt
fi
m -it
11 I
-
just represents
the
-
E Series circuit rules : v R
..... L
internal resistance
As the
temperature increases so does ste resistance .
This is
2
=
I(R +
r)
-> the current
(since there
is the some at a l l
junctions)
points Er V2
grad
are so
because the undert cat
flow as fast because the
particles T
- terminal pd
iside wire
-> emt is split between components (ent =
V +
V2 +
Vz )
moving
,
the are
to slaw He
...
fast enough charge v =
E
# -
> ->
if v is constant , is IR
down /crease rsistener) -
I
so (emt : IR ,
+(R2+IRz ...
)
the greater the current
flowing , concelling
->
out
the less the terminal p d the I's give RCroral) R,
+R2+Ry
=
.
wher conductors because
reated the current inside the cell meas that
.
are more electors have
,
enough a smaller
energy o be viberated so the resistance has a
bigger erect
In charge flows faster .
a
negative temperance
resistance
ficient (NTC) Hermistor Parallel circuit rule :
dureases In series -> total internal registance is
)
with
the sum
temperature ->
current is split at each
junction (F total = 1 , +12 +13 ...
· all the internal resistances of the
RA when cooled to a 'critical temperature' a
->
pd is the across all comparers
same E
wire will become
a
cees (ine more cells
, ~4)
super conductor -> V/R YR
where it is
YRe+ YR
:
toral +
cooled to the
In parallel -> the
,
3
point
...
where there is more cells there are W
no vibration in ,
internal
->
He particles and He resistance decreases cancelling the v's give
resistere is zero IT
---
> I
I (The more caus , ri) Rosal
=
E, z s
...
-Hiy
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