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2023 Portage Learning CHEM 103 Exam 1-6 Final LATEST

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1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. Answer: 1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x 103 2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move d...

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  • September 26, 2023
  • 44
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers

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  • 2023 portage learning chem 103 exam 1 6 final
  • 2023 portage learning chem 103 exam 1 6 final lat
  • 2023 portage learning chem 103 exam 1 6 final lat

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By: proscia44 • 5 months ago

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By: cpmango • 10 months ago

Only used it for the Final and it helped. 2 questions were different on my Final and 1 question was exactly the same as my final from this packet.

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EXAM 1 Question 1 1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. Answer: 1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x 103 2. Convert 4.87 x 10 -6 =negative exponent =smaller than 1, move decimal 6 places = 0.00000487 Question 2 Using the following information, do the conversions shown below, showing all work: 2023 Portage Learning CHEM 103 Exam 1-6 Final LATEST Exam 1-6 1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts 1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints kilo (= 1000) milli (= 1/1000) centi (= 1/100) 1. 2.73 liters x 1000 ml / 1 liter = 2730 ml 2. 8.6 pts x 1 qt / 2 pts = 4.3 qts Question 3 Do the conversions shown below, showing all work: 1. 248oC = ? oK 2. 25oF = ? oC 3. 175oK = ? oF deci (= 1/10) 1. 2.73 liters = ? ml 2. 8.6 pts = ? qts Answer: Answer: 1. 248oC + 273 = 521 oK oC → oK (make larger) +273 1. Show the calculation of the mass of a 17.9 ml sample of chloroform with density of 1.49 g/ml 2. Show the calculation of the volume of 19.4 grams of cresol with density of 1.02 g/ml Answer: 1. M = D x V = 1.49 x 17.9 = 26.7 g 2. V = M / D = 19.4 / 1.02 = 19.0 ml Question 5 1. 1.35601 contains ? significant figures. 2. 0.151 contains ? significant figures. 2. 25oF - 32 ÷ 1.8 = -3.88 oC oF → oC (make smaller) -32 ÷1.8 3. 175oK - 273 = -98 oC x 1.8 + 32 = -144.4 oF oK → oC → oF Question 4 Be sure to show the correct number of significant figures in each calculation. 3. 1.35601 + 0.151 = ? (give answer to correct number of significant figures) Answer:

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