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Exam elaboration for computer organization 2022 questions
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COS26212 Oct/Nov 2022
Oct/Nov 2022
This paper consists of 7 pages plus an appendix.
INSTRUCTIONS
1. Answer all questions on word document/answer sheet, convert to pdf before submitting
2. The mark for each question is given in brackets next to the question.
3. The appendix contains a list of x86 Assembly Language instructions
ALL THE BEST!
MEMORANDUM
, COS2621
3 Oct/Nov 2022
UNIVERSITY EXAMINATIONS
OCTOBER/NOVEMBER 2022
COS2621
Introduction to Programming I
Exam date:2 March 2022
Duration: 2 hrs
Total marks: 90
Welcome to COS2621 exam.
This paper consists of 7 pages.
Instructions:.
• Remember to accept the pledge of Honesty by clicking to activate it
Additional student instructions
1. Students must upload their answer scripts in a single PDF file (answer scripts must not be
password protected or uploaded as “read only” files)
2. Incorrect file format and uncollated answer scripts will not be considered.
3. NO emailed scripts will be accepted.
4. Students are advised to preview submissions (answer scripts) to ensure legibility and that the
correct answer script file has been uploaded.
5. Incorrect answer scripts and/or submissions made on unofficial examinations platforms
(including the invigilator cell phone application) will not be marked and no opportunity will be
granted for resubmission.
6. Mark awarded for incomplete submission will be the student’s final mark. No opportunity for
resubmission will be granted.
7. Mark awarded for illegible scanned submission will be the student’s final mark. No opportunity for
resubmission will be granted.
8. Submissions will only be accepted from registered student accounts.
9. Students who have not utilised invigilation or proctoring tools will be subjected to disciplinary
processes (only include if applicable).
10. Students suspected of dishonest conduct during the examinations will be subjected to
disciplinary processes. UNISA has a zero tolerance for plagiarism and/or any other forms of
academic dishonesty.
11. Students are provided one hour to submit their answer scripts after the official examination
time. Submissions made after the official examination time will be rejected by the examination
regulations and will not be marked.
12. Students experiencing network or load shedding challenges are advised to apply together with
supporting evidence for an Aegrotat within 3 days of the examination session.
13. Students experiencing technical challenges, contact the SCSC 080 000 1870 or email
Examenquiries@unisa.ac.za or refer to URL link for the list of additional contact numbers or
alternatively email your module lecturer. ONLY communication from your myLIfe account will be
considered.
, COS2621
4 Oct/Nov 2022
Question 1: General knowledge [30]
Choose from alternatives (1) to (5) the correct one. Each question counts 2 marks.
a). The exists in one of two states and, in the absence of input, remains in that state.
(1) assert
(2) complex PLD - consists of an arrangement of multiple SPLD-like blocks on a single chip
(3) decoder generates the address of a microinstruction corresponding to the machine instruction to be fetched
(4) flip-flop
(5) oscillators are used to minimize power consumption and provide short startup times.
b). instructions provide computational capabilities for processing numeric data.
(1) Boolean is a result that can only have one of two possible values
(2) Logic data is useful to consider an n-bit unit as consisting of n 1-bit items, each having the value 0 or 1.
(3) Memory is divided into two parts: one part for the OS and one part for the program currently being executed.
(4) Arithmetic
(5)
Comparison is comparing two or more operands; set flag(s) based on outcome
c). NASM is a(n) while DEBUG is a(n) .
(1) compiler, linker and loader
(2) assembler, assembler
(3) assembler, utility to assemble and debug programs
(4) translator, interpreter
(5) compiler, assembler
d). Consider the following assembly language program fragment:
org 0x100
label1: dw 0x76EF
nop
mov ax,ax
nop
Which one of the following statements is true?
(1) 76h is stored in position 101h and EFh is stored in position 100h.
(2) 76h is stored in position 100h and EFh is stored in position 101h.
(3) 67h is stored in position 101h and EFh is stored in position 100h.
(4) 67h is stored in position 100h and EFh is stored in position 101h.
(5) None of the above.
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