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Apuntes ecuaciones diferenciales segundo orden

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Apuntes ecuaciones diferenciales segundo orden

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  • October 8, 2023
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  • 2022/2023
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Ecuaciones diferenciales de segundo orden y
orden superior
General homogénea

y'
"
+
1) 3
y
=




D D =




32 D 0-(D 1) 0
+
+
=




D
=


=

- 1

*x
+
y C1.e c2.
=




+
2)
y y" =0
D =

- 1(m 1) =




13
+ =
D 1 - D(D 1) 0
+
=




D 0 =
cm 2) =




1X
e Cs.e
-



*
C1.e C2-X-
y
+ +

=




+
3) y" y 3
=




+1 3 i
B = -
D -
=
1 0
= =




y C1.ex
=


·COS 1X+ cz.esen 1X
e -



parte parte
real imaginaria
Variación de constantes. Wronskiano

+
y" y
=x

D D =




12 +


B 0 =
-
D(D 1) 0 +
=




D -

= 1


1X

Y GH C1-e
=
(2. -
+




1X
e
x -




yp v
= .
Vz.e
+




Ve Ve
1X -
A I ultima
-




e colocamos o hasta la se CDIOCA
gue
el resultado que te dan de la ecuación.
0 -

efx X


-



derivamos


xe*, dx
* =
=X
e V
ex
V
f x.e
-
=
-

- =
=

, fx
+
dx
*x
V ( *) 0-v
-
-




+ -

x- e =
x- e
=

v =
-

e



((x- e dx) e +()
+ + *
+
ax).e
7x
+
yo c.e (2.e xe-
-
- -




-



=




Ejemplo:

4y" 36y +



COSeC
=

3t 1 =




sen 3t




y" +3,y 1cosec
=
St =




senst
D2 1 0
+

=
c B = -


1 -D 1 =
-

1 0
=
i
=




y C1.e.COS 1x c2.e.sen 1X
+
=




e.COS 1x V2 e-sen 1X
y v. +
.
=




COS 1X sen 1X Ve D



Esenst
=




-



sen COS
1x X vi

COS 1X. VI'+sen 1XV2' 1
=




1X.VI'+cos X. Ve 1 1
sen
-




=




4 sen 3t



Vi =
-sen 1X Ve' =
-




tg (COS X) Ve
CDS 1X



sen x + cosx) v2+COS Ve
X =
sestsVe' (1+sen x tg(Osx))

1
u
-




sen 3t



V2 =
I 1

4 sen3x 1+ se+gcos x)
dX




Vi 1
-
=




tg(CDS X)
4 sen 3t ( 3



v=
1
=

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