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COS3701 Questions and Answers Exams Merged (Easily Searchable)

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Hello, I'm excited to share a valuable resource for your COS3701 exam preparation - a merged and easily searchable PDF of Questions and Answers. This tool is especially useful if your exam allows open-book format, as it enables you to quickly navigate and find the information you need. I pers...

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  • October 9, 2023
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  • Exam (elaborations)
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By: sbmbopape • 10 months ago

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COS3701 exam - Jan 2001
Question 1
(a) Find a CFG for the language consisting of words of odd length over
the alphabet ∑={a,b} that start and end with different letters.

(b) Convert the following CFG to Chomsky Normal Form (CNF):
S 🡪 AA
A 🡪 B | BB
B 🡪 abB | b | bb

Question 2
Draw a deterministic PDA that accepts the language
L = { (ba) (ab) | n 0 } over the alphabet ∑={a,b}

Question 3
The pumping lemma with length for context-free languages (CFLs) can be
stated as follows:

Let L be a CFL generated by a CFG in CNF with p live productions. Then
any word w in L with length(w) > 2 can be broken into 5 parts:
w = uvxyz
such that
length(vxy) ≤ 2
length(x) > 0
length(v) + length(y) > 0
and such that all words uvⁿxyⁿz with n {2,3,4,…} are also in the
language L.

Use the pumping lemma with length to prove that the language
L = { a b a b | n, m = 1, 2, 3...}
over the alphabet ∑={a,b} is NOT context-free.

Question 4
Give an informal justification by means of grammars to show that the
context-free languages are closed under product.

Question 5
Draw a TM that accepts all words ending in aaa, crashes on all words
ending in baa, and loops on all other words over the alphabet Σ = {a,
b}.

Question 6
Consider the non-context-free language L over the alphabet Σ = {a, b},
which is defined as
L = { a b a | n = 1, 2, 3...}

(i) Explain in words how you would build a 2PDA that accepts the
language L. Do NOT draw a machine.

,(ii) Can you build a 3PDA that accepts L? Justify your answer without
attempting to give a 3PDA or an algorithm.

(iii) Can you build a TM that accepts L? Justify your answer without
attempting to give a TM or an algorithm.

(iv) Can you build a PDA that accepts L? Justify your answer without
attempting to give a PDA or an algorithm.

Question 7
What are Accept(T), Loop(T), and Reject(T) of the following TM T?




Question 8
a) When is a language regular? Give your answer in terms of
machines.
b) When is a language context-free? Give your answer in terms of
machines.
c) When is a language recursively-enumerable? Give your answer in
terms of TMs.
d) When is a language recursive? Give your answer in terms of TMs.
e) Explain the idea of the encoding of a TM.

Question 9
(a) What does it mean for a function to be computable?

(b) Prove that the predecessor function defined by
PREDECESSOR(N) = n - 1 for all n ≥ 1
is computable. Use unary encoding.

, Solutions
Question 1a




Assuming that the FA is correct, Cohen’s Theorem 21 can be applied,
which results in the following CFG:

S 🡪 aX | bP
X 🡪 aY | bY
Y 🡪 aX | bZ
Z 🡪 aY | bY | /\
P 🡪 aQ | bQ
Q 🡪 aR | bP
R 🡪 aQ | bQ | /\

Question 1b
Step 1 - Kill all /\ productions:

There are no /\ productions, so none of the non-terminals is nullable.
The CFG remains unchanged.

Step 2 - Kill all unit productions:

The only unit production is A 🡪 B, where the B can be replaced with
all B’s non-unit productions (i.e. all of them).

The new CFG, without unit productions, is:

S 🡪 AA
A 🡪 BB | abB | b | bb
B 🡪 abB | b | bb

Step 3 - Replace all mixed strings with solid nonterminals.

, Create extra productions that produce one terminal, when doing the
replacement.

The new CFG, with a RHS consisting of only solid nonterminals or one
terminal is:

S 🡪 AA
A 🡪 BB | XYB | b | YY
B 🡪 XYB | b | YY
X 🡪 a
Y 🡪 b

Step 4 - Shorten the strings of nonterminals to length 2.

Create new, intermediate nonterminals to accomplish this.

The new CFG, in CNF is:

S 🡪 AA
A 🡪 BB | RB | b | YY
B 🡪 RB | b | YY
R 🡪 XY
X 🡪 a
Y 🡪 b

Question 2

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