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Pearson Edexcel GCE Chemistry Advanced Subsidiary PAPER 2 Core Organic and Physical Chemistry June 2023 $15.99
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Pearson Edexcel GCE Chemistry Advanced Subsidiary PAPER 2 Core Organic and Physical Chemistry June 2023
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  • GCE In Chemistry
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  • PEARSON (PEARSON)

Pearson Edexcel GCE Chemistry Advanced Subsidiary PAPER 2 Core Organic and Physical Chemistry June 2023

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Document information

  • October 24, 2023
  • 32
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers

Subjects

  • pearson edexcel level 3 gce
  • pearson edexcel gce chemistry advanced subsidiary
  • paper 2 core organic physical chemistry june 2023

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  • A/AS Level
  • PEARSON (PEARSON)
  • GCE In Chemistry
  • GCE In Chemistry
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Please check the examination details below before entering your candidate
information
Candidate surname Other names

Centre Candidate
Number Number


Pearson Edexcel Level 3
GCE
Tuesday 23 May 2023
Paper
Morning (Time: 1 hour 30
minutes)
referenc
e
8CH0/02
 
Chemistry
Advanced Subsidiary
PAPER 2: Core Organic and Physical
Chemistry
You must have: Total
Scientific calculator, Data Booklet, ruler Marks



Instructions
• Use black ink or ball‑point pen.
• IfFillpencil is used for diagrams/sketches/graphs it must be dark (HB or B).
• centre number
in the boxes at the top of this page with your name,
and candidate number.
•• Answer all
Answer the questions in the spaces
provided – there may be more space than
you need.
questions.

Information
• The total mark for this paper is 80.
• The marks for each question are shown in brackets
– use this as a guide as to how much time to spend on each question.
• For the question marked with an asterisk (*), marks will be awarded for your
ability to structure your answer logically, showing the points that you make are
related or follow on from each other where appropriate.
• A Periodic Table is printed on the back cover of this paper.

Advice
• Read each question carefully before you start to answer it.
• Show all your working in calculations and include units where appropriate.

• Check your answers if you have time at the Turn over

end.



1

, Answer ALL questions.

Some questions must be answered with a cross in a box . If you
change your mind about an answer, put a line through the box and
then mark your new answer with a cross .

1 This question is about collision theory.
The Maxwell‑Boltzmann distribution of molecular energies for a reaction at a
particular temperature is shown in the graph.
Add another line on the graph to represent the same reaction with the same
number of particles at a higher temperature.




Number of
particles with
energy, E




Energy, E

(Total for Question 1 = 2 marks)




2


,2 This question is about alkanes and some of their reactions.
(a) Hexane is a saturated hydrocarbon.
State what is meant by the term ‘saturated hydrocarbon’.
Your answer should refer to both words in the term.
(2)

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(b) When methane reacts with gaseous chlorine, the initiation step is bond
breaking in the chlorine molecule to form chlorine free radicals.
The equation for this step is shown.

Cl2(g) → 2Cl•(g)

Two equations for the propagation step are shown.

Cl•(g) + CH4(g) → CH3•(g) + HCl(g)
CH3•(g) + Cl2(g) → CH3Cl(g) +
Cl•(g)

(i) Write the overall equation for this reaction of methane with
chlorine. State symbols are not required.
(1)




(ii) Calculate the maximum mass, in grams, of chloromethane produced
when
7.00 g of chlorine gas reacts completely with excess
methane. [Molar mass of CH3Cl = 50.5 g mol–1] (2)




3
 Turn
over

, (iii) Write an equation for a termination step for this
reaction. State symbols are not required.
(1)




(iv) Further substitution of chloromethane can occur, producing
dichloromethane, which is a liquid at room temperature.
Calculate the maximum volume, in cm3, of dichloromethane liquid that
could be produced from 12.5 g of chloromethane.
Give your answer to an appropriate number of significant figures.
(3)

CH3Cl(g) + Cl2(g) → CH2Cl2(l) + HCl(g)

[Density of dichloromethane, CH2Cl2(l) = 1.32 g cm–3]




4


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