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oplossingen oefeningen hoofdstuk 1 statistiek
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alle A en E reeks oefeningen worden hierin opgelost (enige die nodig zijn voor TEW)
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of 1 A . .I
0 A = < RRR , 555] ,
b) B =
(RCS 154, RS SR SRL S[R]
, , ,
,
C) C =
[RRL RRS RR SRR RLR BSR]
, , , , ,
ol D =
SRRL RRS MIR RSR RB SRR
, , R S
(B) S2
,
RL
, , , , , ,
, ,
SL
,
SSR
,
SSC
,
SRS
,
SCS
,
RSS
,
553
e) D =
[PRB, C
,
SSS RLS RSC
,
LRS
,
LSR SL SCRY
, , , ,
↳omdot CD CUD= Den CrD = <
,
off1 .
A 2 .
a) b =
[SS , SSF ,
SFS
,
SFF, FSS FSF FFS
, , ,
FFF3
b) A = [SSF ,
SFS
, FSS]
c) B =
[SSS ,
SSF
,
SFS
FSS]
,
or C = SSSS ,
SSF
,
SFS]
e) C =
SSFF ,
FSS
,
FSF FFS
, ,
FFFY
Aus=E FSS]
????s /
SFS,
E
A1C =
SSS SSF SFS FSS]
BU ? ssS
/
,
F
,
SFSY
/
of 1 A 3
.
.
N
P(A) 5jP(B) 0 4
; P(AB) 0 25
=
0 =
=
, , ,
c) P(A) +
P(B) = 0
,
9 -
0
,
25 = 0
,
65
25
b) P(AUB)
-,
= 1 -0, 65 =
0 35
,
c) P(A)B) =
P(A) -
P(A1B) = 0
,
5-0 25=
,
0
,
25
, of 1 A .
. 4
P(A) ; P(B)
0 5
0
35
=
=
, ,
a) Erkunnen ook ander sochen uitgeland worden
b) P(A) 1 PCA) 0 65 =
-
=
,
C) P(AUB) P(A) + P(B) 85
= =
0
,
o P(AUB) = 1 -
0
,
85
.
= 0
,
15
in de b gemabt
-
47D15 lampen in totoa
T
of
L
1A 5 . .
200 :
52 : 5 X
is
/stone e Peter
-
6 : 6X 75
zlag
P/nyomaganbn)
:
6w
=
p/sfa zelous
ganzer name)- ...
of 1 .
A 6 .
·P(A) =
0
,
7
hogrobutes offruit
P(B) I vees of vis
boopt
=
0
P(C) = 0 75
boot
backen of say
,
P(AUB) 85 98)
; P(AUC) 99P(BUC) 95
; P(AUBUC)
=
0
=
= 0 0 0
, , =
, .
,
a) P(AUBUC) =
0
,
98
b) 1- PCAUBUC) = 0
,
02
cen d
on volgende Als
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