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AQA GCSE COMPUTER SCIENCE Paper 2 Computing concepts June 2023
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AQA GCSE COMPUTER SCIENCE Paper 2 Computing concepts June 2023
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GCSE COMPUTER SCIENCEPaper 2 Computing concepts
6/1/2023
GCSE COMPUTER SCIENCE Paper 2
Computing concepts
,hj
AQA
GCSE
COMPUTER SCIENCE
Paper 2 Computing concepts
Materials
There are no additional materials required for this paper.
You must not use a calculator.
Instructions
Use black ink or black ball-point pen. Use pencil only for drawing.
Answer all questions.
You must answer the questions in the spaces provided.
If you need extra space for your answer(s), use the lined pages at
the end of this book. Write the question number against your
answer(s).
Do all rough work in this book. Cross through any work you do
not want to be marked.
Information
The total number of marks available for this paper is 90.
Advice
For the multiple-choice questions, completely fill in the lozenge alongside the
appropriate answer.
CORRECT METHOD WRONG METHODS
If you want to change your answer you must cross out your original answer as shown.
If you wish to return to an answer previously crossed out, ring the answer you now
wish to select as shown.
*Jun23525201*
8525/2
2
, 2
Do not write
Answer all questions in the spaces outside the
box
provided.
0 1 .1 The number base 2 is called binary.
Shade one lozenge to show which number base is called hexadecimal.
[1 mark]
A 6
B 8
C 10
D 16
0 1
.2 Shade two lozenges to show the statements that are true about
hexadecimal.
[2 marks]
A Hexadecimal can represent a greater range of numbers than binary.
B Hexadecimal is easier for people to read than binary.
C Hexadecimal is faster for a computer to process than binary.
D Hexadecimal is more accurate than binary.
E Hexadecimal takes less space in RAM than binary.
F Hexadecimal takes less time to type than binary.
0 2 .1 Convert the decimal number 171 into
binary. [1 mark]
*02
IB/G/
* Jun23/8525/2
, 3
Do not write
outside the
0 2 .2 Convert the hexadecimal number 2D into box
binary.
You should show your working. [2
marks]
Answer
0 3 Add together the following three binary numbers and give your answer in
binary.
[2 marks]
0 1 0 1 1 0 0 0
0 0 0 1 1 0 0 1
+ 0 1 0 0 1 0 1 1
0 4 Convert 16 000 000 bits to megabytes (MB).
You should show your working.
[2 marks]
Answer MB
*03
IB/G/
* Jun23/8525/2
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