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Wiskunde B 4vwo moderne wiskunde oefentoets ANTWOORDEN hoofdstuk 5 $3.21
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Wiskunde B 4vwo moderne wiskunde oefentoets ANTWOORDEN hoofdstuk 5

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  • Course
  • Wiskunde B
  • Level
  • VWO / Gymnasium
  • Book
  • Moderne Wiskunde vwo 4 wiskunde B leerboek

de antwoorden op de oefentoets van hoofdstuk 5 'lijnen' moderne wiskunde B 4 vwo. super handig want je kunt duidelijk zien wat je fout gedaan hebt en van je fouten leren zodat je ze niet meer maakt tijdens het proefwerk. de kans op een hoger cijfer stijgt hierdoor omdat je de stof al eens als proef...

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Document information

  • May 25, 2018
  • 4
  • 2017/2018
  • Exam (elaborations)
  • Answers

Subjects

  • wiskunde b
  • moderne wiskunde
  • antwoorden
  • 4 vwo
  • oefentoets

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Written for

  • Secondary school
  • VWO / Gymnasium
  • Wiskunde B
  • 4
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2  reviews

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By: frankvermeer • 4 year ago

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By: wiepdejong • 4 year ago

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The elaborations could be even clearer.

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MODERNE WISKUNDE 11E EDITIE 4 VWO B HOOFDSTUK 5 PROEFWERK 1




H5 Lijnen Proefwerk 1
Uitwerkingen en normering
1 Het snijpunt met de x-as is (3, 0). 2
a Het snijpunt met de y-as is (0, 5).

b x y 3
 1
3 5
5 x  3 y 15
 3 y  5 x  15
y  53 x  5
5
De richtingscoëfficiënt van l, dus ook van m is 3 .
m : y  53 x  b gaat door (3, 7), dus 7  53 3  b, dus b 2.
5
Oplossing is m : y  3 x  2.
c 5 4
De richtingscoëfficiënt van l is 3 (zie opdracht b).
3
De richtingscoëfficiënt van p is  5 .
3
p : y  5
x  b gaat door (2, 0), dus 0  53 2  b .
1 3
Hieruit volgt b 1 5 , dus p : y  5
x  1 15 .
5 y  3x  6
3x  5 y 6

2 x  5 4( y  5) 2
a
b Vergelijking 1 is te schrijven als x 7 y  30. 3
Invullen in vergelijking 2 geeft 7 y  30  5 4( y  5).
7 y  25 4 y  20
3 y 45
y 15
Hieruit volgt x 7 15  30 75.
Oma is 75 jaar en Iris is 15 jaar.

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