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Wiskunde B 4vwo moderne wiskunde oefentoets ANTWOORDEN Vaardigheden 3 $3.26   Add to cart

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Wiskunde B 4vwo moderne wiskunde oefentoets ANTWOORDEN Vaardigheden 3

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de antwoorden voor vaardigheden 3 moderne wiskunde b 4vwo. je hebt de vaardigheden getraind en er even voor gezwoegd, nu wil je natuurlijk weten hoe je gescoord hebt voor deze oefentoets. de antwoorden geven je een goed beeld hoe je ervoor staat en je kunt hierdoor van je fouten leren en het op de ...

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  • May 25, 2018
  • 2
  • 2017/2018
  • Exam (elaborations)
  • Unknown
  • Secondary school
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By: mb0123 • 6 year ago

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MODERNE WISKUNDE 11E EDITIE 4 VWO B VAARDIGHEDEN 3 PROEFWERK 1




Vaardigheden 3 Proefwerk 1
Uitwerkingen en normering
1a 13 5 87 52  25  174 97 1
2 53  1 14  8 10
7
      4 17
20
5 4 10 20 20
b  4p 3p 1 1  3p 2 2
 2   
8p 9p 2 3p 6p
c 3 3 6 3ab  3b(a  b)  6a(a  b) 3ab  3ab  3b 2  6a 2  6ab  6a 2  3b 2 2
    
ab a b ab(a  b) ab(a  b) ab(a  b)
d 2 23 8 2 16 2
  
32 3
1
7 21
e 2
5 1 25 26 2
a
 2 a2
 2
 2 2
4a 5 2a 2a 2a
f b 2b ac 2b 2 ac 2b 3  3a 2c 2 2
    
a 3c b 3ac b 3abc

2a 8a  128a 2 2a  8 2a  6 2a 1
b 2
a 169a3  16a5 13a 2 a  4a 2 a 17a 2 a
c
2  2
2
8  6 32 3 (4 2  24 2) 2 3 400 2  3 800 3
d 4 2
 3 3  16 27  6
3 8 9 8


3a  2 x  5 5 x  2  x 1 en dit geeft y 3. Het snijpunt is (1, 3). 2
b Richtingscoëfficient k  richtingscoëfficient m, dus vergelijking k: y 5 x  p. 2
Door P (5, 5), dus p  20. Antwoord: k : y 5 x  20
c 1 1 2
Lijn loodrecht op l: y  2 x  q . Door P (5, 5), dus q  2 2
1 1
Snijpunt met l:  2 x  5  2 x  2 2  x 3 dus snijpunt (3, 1).
Afstand: (5  3) 2  (5  1) 2  20 2 5
d Richtingshoek l: tan  1 (2)  63,43 en richtingshoek m: tan  1 (5)  78,69 2
Hoek l en m: circa 180  63,43  78,69  38

4 Δy 4  3 2
a Richtingscoëfficiënt l:  1, l door P (1, 2), dus l : y  x  1
Δx 2 1
b Er geldt (van P naar Q): g 3 1 4  2, dus g  2, want  2 voldoet niet. 2
Met (1, 2) : 2 b  2, dus b  2.

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