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Solutions for Turbomachinery, Concepts, Applications and Design, 1st Edition Murty (All Chapters included) $29.49   Add to cart

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Solutions for Turbomachinery, Concepts, Applications and Design, 1st Edition Murty (All Chapters included)

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Complete Solutions Manual for Turbomachinery, Concepts, Applications and Design, 1st Edition by V. Dakshina Murty. ; ISBN13: 9781138640696. (Full Chapters included Chapter 1 to 12)....Chapter 1 solutions not available. 1. Introduction and History 2. Dimensional Analysis 3. Theory of Turbomachines...

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  • January 25, 2024
  • 345
  • 2018/2019
  • Exam (elaborations)
  • Questions & answers
  • Auto Industry
  • Auto Industry
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Solutions Manual
To accompany

Turbomachinery
Concepts, Applications, and Design

By

V. Dakshina Murty



Complete Chapter Solutions Manual
are included (Ch 1 to 12)



** Immediate Download
** Swift Response
** All Chapters included

,2.1 The rotor diameter of a pump is 40 cm. It delivers 3 m3/min while rotating at 1800 rpm. A
geometrically similar pump has a diameter of 30 cm and rotates at 3600 rpm. What would be the
flow rate of the second pump? Also if the head on the first pump is 15 m, what head would the
second pump deliver?

Given:
Pump 1 Pump 2
𝐷1 = 40 𝑐𝑚 = 0.4 𝑚 𝐷2 = 30 𝑐𝑚 = 0.3 𝑚
𝑚3 𝑚3 𝑄2 = ?
𝑄1 = 3 = 0.05
min 𝑠
𝑟𝑎𝑑 𝑟𝑎𝑑
𝑁1 = 1800 𝑟𝑝𝑚 = 188.5 𝑁2 = 3600 𝑟𝑝𝑚 = 377
𝑠 𝑠
𝐻1 = 15 𝑚 𝐻2 = ? ?

Solution:

Assume: Geometrically similar

Flow Coefficient φ is same for both pumps.
𝑄1 𝑄2 𝑄1
= ⟹ 𝑄2 = (𝑁2 𝐷23 )
𝑁1 𝐷13 𝑁2 𝐷23 𝑁1 𝐷13
𝑚2
0.05 𝑟𝑎𝑑 𝑚3
𝑄2 = 𝑟𝑎𝑑
𝑠
(377 𝑠
) (0.3 𝑚)3 = 2.53 𝑠
(188.5 𝑠 )(0.4𝑚)3


Head coefficient ψ is same for both pumps

𝐻1 𝐻2 𝐻1
2 2 = 2 2 ⟹ 𝐻2 = 2 2
(𝑁22 𝐷22 )
𝑁1 𝐷1 𝑁2 𝐷2 𝑁1 𝐷1
13𝑚
𝐻2 = (3600 𝑟𝑝𝑚)2 (0.3𝑚)2 = 33.75 𝑚
(1800 𝑟𝑝𝑚)2 (0.4𝑚)2

Pump 1 Power
𝛾1 𝑄1 𝐻1 (9810)(0.03 𝑚2 ) (13𝑚)
𝑃1 = = = 9.4 𝑘𝑊
𝐻1 0.78


Pump 2 Power
𝑚3
𝛾2 𝑄2 𝐻2 (9810)(0.05 )(33.75𝑚)
𝑃2 = 𝐻1
= 𝑠
0.78
= 17.9 𝑘𝑊

, 2.2 A pump delivers 2250 gpm against a head of 95 ft when the rotating at 1450 rpm. What
would be its specific speed? What type of pump would this be? If the speed of the pump is
changed to 1200 rpm, what would be the new head and flow rate?

Given: Pump is 2250 gpm against H = 95 ft rotating at 1450 rpm.

Solution:

𝑁√𝑄 𝑟𝑒𝑣 𝑟𝑎𝑑 1 𝑚𝑖𝑛 𝑟𝑎𝑑
𝑁𝑆 = 3 𝑁 = 1450 × 2𝜋 × = 151.84
(𝑔ℎ)4 𝑚𝑖𝑛 𝑟𝑒𝑣 60 𝑠 𝑠

𝑄 = 2250 𝑔𝑝𝑚 = 5.01 𝑐𝑓𝑠

151.8 × √5.01
𝑁𝑆 = = 0.83, centrifugal pump
[ (32.2)× (95 )]0.75


@ 1200 rpm

𝑟𝑎𝑑
𝑁2 = 1200 𝑟𝑝𝑚 × 2𝜋 × 1/60 = 125.66
𝑠

Head Coefficient:
𝑔𝐻1 𝑔𝐻2 95 𝐻2
2
𝐷 𝑁 2 = 2
𝐷 𝑁 2 ⟹ 151.84 2
= 125.62
1 1 2 2
𝐻2 = 65 𝑓𝑡

Flow Coefficient:
𝑄1 𝑄1 2250 𝑄2
3 = 𝑁 𝐷 5 ⟹ 1450 = 1200
𝑁1 𝐷1 1 2
𝑄2 = 1862 𝑔𝑝𝑚

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