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PHYSICS 1300
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Physics 1300 Study Notes - Sept. 2023 - Sept. 2024
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Electric potential EnergyThe energy related the electric
to
charge particle due to its location in
·
field depending on its
position
Similar where the
to
gravitational potential energy related
·
energy
w) the due to its the
mass is location in
gravitational field ~Ep mgy =
the
u =
qE y due
q Q# uniform field to plate
electric
of charge
:
proton located in a
uniform electric
field of magnitude ISONIC
created
by negatively charged plate Proton .
is 1 0 m
.
from the plate
a) what is electric
potential energy relative to plates
b) what direction released ? does /U) increase
is
of proton when or
decrease once released ?
0)
a) U =
gEy = (16 X10" ) ( (S0) (1 .
2 4
= . X 10- J
b) the downward towards theplate because of the
proton will move
negative charge on the plate and the potential energy will lower
,
the
to the plate as electric
field lines are moving further apart
Q #2
electron is located
a in a
uniform electric
field of ISONIC ,
1 Om.
away from plate
a) (v) relative to plate ?
b) What direction will it move ? (v) increase or decrease ?
a) U =
qEy = 1 6 X10"4)
. (150) (1 0) .
= -
2 . 4 x 10. j
b) electron will move
upward away from the
plate as the
plate has a
negative charge ,
the (U) will increase of the electric
field lines will move closer x
↳ the (U) will lower the
as it
gets further from plate
, Another
way of approaching conservation
of energywi uniform
electric
field is
Vi + Exel = Uzt Elez
U
1, electric
U2 :
potential energy
Ele , Ely Kinetic
energy =
-DER
Q#
electron starts 5 2 cm
from rest at .
from positively charged
plate . A
uniform electric
field or a
magnitude of 220 NIC is formed
.
what is the speed of the electron
before it hits the plate.
Let the plate be O
-
&
E = 220N/C LU =
Up-Vi >
-
g Y GE Yi
v = 0 OS2M
.
=
.4
= 1 6 x 10 C
q
.
electron " (0) ( 6 x 10 P) /220) 70 0S2)
4 11 A10
Reg
:
= -
mass
of = . .
.
10"0
1 0304 x
&
= -
.
SAMPLEQ#
positively charged plate produces
O En = -
OU
1 3 . X/03 NIC
. Electron is released OEK = -
1 . 8304 X 10. 18j
from rest at a
position that is DEL =
< mu 2
1 2 X 10
away from plate
. m . What
if hits the 2(1 8304x10
-
18)
is the
speed as plate ? vg
= .
& (1 X/0
-
3)
the that
Yo position
-
= 0 as is when the
°
electron hits the . 2
plate = .
00 x 10 m/S
gEy-gEY9) (1
-
ou =
= 10) -
/- 1 6
. x 10" . 3 x 10") / 1 2 x 10
.
m)
18
2 446 X10 J
-
= .
·Ex = - OU
%8
OEK = -
2 . 446x10 ju
I mu
2
OEK =
=
vq =
26 2:
.
446x10-8)
31
4 /1 X10
-
.
"
= 2 34/X10
.
mrs
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