100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Portage Learning Chemistry CHEM 103 Unit 2 graded A+ by experts 2024/2025 $11.49   Add to cart

Exam (elaborations)

Portage Learning Chemistry CHEM 103 Unit 2 graded A+ by experts 2024/2025

 3 views  0 purchase
  • Course
  • CHEM 103 Chemistry
  • Institution
  • CHEM 103 Chemistry

Portage Learning Chemistry CHEM 103 Unit 2 graded A+ by experts 2024/2025

Preview 2 out of 10  pages

  • April 20, 2024
  • 10
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
  • CHEM 103 Chemistry
  • CHEM 103 Chemistry
avatar-seller
Ascore
Portage Learning Chemistry CHEM 103
Unit 2


1. Ca3N2
Ca 3 x 40.08 = 120.24
N 2 x 14.01 = 28.02
120.24 + 28.02 = 148.26

2. Li3PO4
Li 3 x 6.941 = 20.823
P 1 x 30.97 = 30.97
O 4 x 16.00 = 64.00
20.823 + 30.97 + 64.00 = 115.793

3. NH4NO3
N 2 x 14.01 = 28.02
H 4 x 1.008 = 4.032
O 3 x 16.00 = 48.00
28.02 + 4.032 + 48.00 = 80.052
Number your answers, and show your work. Be sure to give answers with the correct units.
Calculate the molecular weight of the following compounds:

1. Ca3N2 ____________________

2. Li3PO4 ____________________

3. NH4NO3 ____________________


1.

MW of NH4NO3 = 80.052

moles = 10..052 = 0.125 mole

2.

MW of Li3PO4 = 115.793

, grams = 0.0500 x 115.793 = 5.79 grams

Number your answers, and show your work. Be sure to give answers with the correct units.

Calculate the number of moles in 10.0 grams in the following compound:

1. NH4NO3 ____________________

Calculate the number of grams of each in 0.0500 mol in the following compound:

2. Li3PO4 ____________________




Brainpower
Read More
Previous
Play
Next
Rewind 10 seconds
Move forward 10 seconds
Unmute
0:00
/
0:00
Full screen
1. MW of Na2SO4 = 2 (22.99) + (32.07) + 4(16.00) = 142.05

%Na = 45..05 x 100 = 32.37%

%S = 32..05 x 100 = 22.58%

%O = 64..05 x 100 = 45.05%

2. MW of Ca(NO3)2 = (40.08) + 2 (14.01) + 6 (16.00) = 164.1

%Ca = 40..1 x 100 = 24.42%

%N = 28..1 x 100 = 17.07%

%O = 96..1 x 100 = 58.50%

Calculate the percent of each element present in the following compounds:

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller Ascore. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $11.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

67096 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$11.49
  • (0)
  Add to cart