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Algemene chemie oefeningen hoofdstuk 3
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Chemie oefeningen hoofdstuk 31. Balanceer volgende reacties:
a) Mg+HNO3→H2+Mg(NO3)2
b) CaC2+H2O→Ca(OH)2+C2H2
c) CH4+Cl2→CH2Cl2+HCl
d) NH3+CO2→CH4N2O+H2O
e) Co2O3(s)+C(s)→Co(s)+CO2(g)
f) C4H10(g)+O2(g)→CO2(g)+H2O(g)
Oplossing:
a) Mg+2HNO3→H2+Mg(NO3)2 b) CaC2+2H2O→Ca(OH)2+C2H2
c) CH4+2Cl2→CH2Cl2+2HCl d) 2NH3+CO2→CH4N2O+H2O
e) 2Co2O3(s)+3C(s)→4Co(s)+3CO2(g) f) 2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
2. Wat is de massa van 0.500 mol CCl4?
Oplossing:
m = n * M = 0.5 * M = 76.9 g
3. De gebalanceerde reactie voor C2H2 met zuurstof is 2 C2H2 + 5 O2 → 4 CO2 + 2 H2O. Hoeveel gram
zuurstof is nodig om te reageren met 0.13 g C2H2?
Oplossing:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
0.13 g ?
n = m / M = 0.005 mol n / 2 * 5 = 0.0125 mol voor O2 m = n * M = 0.400 g
4. Hoeveel gram calcium chloride is nodig om 1.50 g kalium chloride te produceren volgens CaCl2(aq)
+ K2CO3(aq) → 2KCl(aq) + CaCO3(aq)
Oplossing:
CaCl2(aq) + K2CO3(aq) → 2KCl(aq) + CaCO3(aq)
? 1.5 g
n = m / M = 1..55 = 0.0201 mol n / 2 = 0.01006 mol m = n * M = 1.12 g
5. Hoeveel mol is 5.00 * 1022 moleculen NaF?
Oplossing:
𝑀𝑜𝑙𝑒𝑐𝑢𝑙𝑒𝑛 5.00∗1022
𝐴
= 6.02∗1023 = 0.083 mol
6. Als 0.72 g water volledig weg reageert in volgende reactie: 2 H2O → 2 H2 + O2, wat is de massa H2?
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