Section 4: Propose a structure for an unknown compound using combined spectral analysis
Compound R
Percentage elemental composition:
Carbon: 54.5% Hydrogen: 9.1% Oxygen: 36.4%
IR Spectra
1H NMR
13C NMR
,Mass Spectrum
Empirical Formula:
Percentage Elemental Composition:
, Carbon: 54.5% Hydrogen: 9.1% Oxygen: 36.4%
Empirical Formula calculation:
Step1
53.5% = 53.5g
9.1% = 9.1g
36.4% = 36.4g
Step 2
53.5g/ 12= 4.5
9.1g/ 1 = 9.1
36.4g/ 16 = 2.3
Step 3
4.5/2.3 = 2
9.1/2.3 = 4
2.3/2.3 = 1
Emperical Formula: C2H4O
Molecular Formula:
Mr of Emperical Formula: (2X12)+16+4 = 44
Mass Spectrum:88
Molecular Formula: 88/44 = 2
C2H4O x 2 = C4H8O2
IR Identififcation:
Wavelength: Functional Group:
2900 C-H
1750 C=O
1000+1200 C-O
Possible functional group:
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