Exam (elaborations)
Entregas Obligatorias AA
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Entregas obligatorias de ejercicios análisis ambiental
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ANÁLISIS QUÍMICO AMBIENTALACTIVIDAD 2 (fecha de entrega 15 de marzo de 2024)
ALUMNO Fatima Zohra Saffar
PROBLEMA
La cantidad de hierro presente en un meteorito se determinó mediante una valoración redox
en la que se utilizó como agente valorante KMnO4. Para ello, se disolvió una muestra de
0,8175 g en ácido y el Fe3+ liberado se redujo cuantitativamente a Fe2+ usando una columna
reductora. La valoración con KMnO4 0,125 N precisó 41,3 mL para alcanzar el punto final.
Determinar el porcentaje en peso de Fe2O3 en la muestra de meteorito.
Datos: Pat (Fe)= 55,85 g/mol Pat (O)= 16 g/mol
CÁLCULOS
Masa de la muestra= 0.08175g
Agente Valorante= KMnO4 0,125 N precisó 41,3 mL
Reacción:
Fe3+ + 1e ↔ Fe2+
Eq KMnO4 = N*V=0.125 N *0.0413L = 0.0051625
Eq KMnO4 = Eq Fe = Eq Fe2O3
Masa Fe2O3= (eq Fe2O3)*( P.eq)= (eq Fe2O3)*(P. molar/Valencia)= 0.0051625 *
(159.7 g/mol / 2)= 0.4122
% Fe2O3 = (0.4122/0.8175)*100= 50.425%
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