Statistics: The Art and Science of Learning from Data
Extra uitgewerkte opdrachten voor BIS, of met antwoorden, gevolgd aan de Faculteit Sociale Wetenschappen (VU, bachelorjaar 1). Laatste pagina's zijn oefenopdrachten zonder uitwerking!
Samenvatting Beschrijvende en Inferentiele statistiek (BIS)
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Vrije Universiteit Amsterdam (VU)
Communicatiewetenschap
Beschrijvende en inferentiële statistiek (S_BIS)
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College 8 oefeningen
Oefeningen
College 1
Oefening 1
Bij 68%
X+1s=15,09
X-1s=12,37
Dus C.
Oefening 2:
Gewogen gemiddelde berekenen
(8*4)+(13*3)=
(32)+(39)=71
71:21=3,38
Dus B.
Oefening 3:
,Het is dan Modus, mediaan, gemiddelde. Dus A.
Oefening 4:
68%:
Y+1s=33,8
95%:
Y+2S=37,5.
Dus B.
College 2
Oefening 1: Oefeningen, en wat zal de ware gemiddelde lengte zijn van mannen en
vrouwen?
Z-score berekenen:
Z=(x-x̅)/s
Z=(166-170,6)/6,5
Z=-0,71
P-waarde:
P=0,2389
0,2389*100=23,89
Dus 23,89% van de populatie is kleiner dan ik.
Ware lengte vrouwen:
1,96*6,5=12,74
,170,6-12,74=157,86
170,6+12,74=183,34
Dus de ware lengte ligt tussen de 157,86 en 183,34 centimeter.
Ware lengte mannen:
1,96*7=13,72
184+13,72=197,72
184-13,72=170,28
Dus de ware lengte ligt tussen de 170,28 en 197,72 centimeter.
Oefening 2:
Bij s=2000:
Berekenen z-score:
Z=(x-x̅)/s
Z=(43000-30000)/2000
Z=6,5
P-waarde:
6,5*2000=13000
Bij s=10000:
Berekenen z-score:
Z=(x-x̅)/s
Z=(43000-30000)/10000
Z=1,3
P-waarde en kritieke waarde:
P=0,9032
1-0,9032=0,0968
0,0968*100=9,68%
Oefening 3:
Gemiddelde en standaarddeviatie X berekenen:
2+5+6=13
, 13/3=4,33
s=√(x-x̄)2/n-1
s=√((2-4,33)2+(5-4,33)2+(6-4,33)2)/3-1
s=√(5,43+0,45+2,79)/2
s=2,082
Gemiddelde en standaarddeviatie Y berekenen:
1+1+2=4
4/3=1,33
s=0,577
Correlatie formule invullen:
Y=a+b*x
Y=2,5+0,45*9
Y=6,55
Dus een score van 6,55.
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