Exam (elaborations)

Chem 103 Module 1 to 6 Exam answers Portage learning latest complete update

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Module
CHEM 103

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Portage Learning

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Type Exam (elaborations)
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chem 103 module 1 to 6 exam answers portage learni

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Portage Learning
Module
CHEM 103

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Chem 103 Module 1 to 6 Exam answers Portage learning
latest complete update

MODULE 1 EXAM
Question 1
Click this link to access the Periodic Table. This may be helpful
throughout the exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.

1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places
= 8.453 x 102
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5
places = 0.0000321

Question 2
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

Using the following information, do the conversions shown below, showing all
work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4
quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= centi (=
1/100) 1/1000) deci (= 1/10)

1. 24.6 grams = ? kg

2. 6.3 ft = ? inches

1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg
2. 6.3 ft x 12 in / 1 ft = 75.6 inches

please always use the correct units in your final answer

Question 3

,Click this link to access the Periodic Table. This may be helpful throughout
the exam.

Do the conversions shown below, showing all work:
1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ? oF

1. 28oC + 273 = 301 oK o
C → oK (make larger)
+273
2. 158oF - 32 ÷ 1.8 = 70 oC o
F → oC (make smaller)
-32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF K → oC → oF
o

Question 4
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

Be sure to show the correct number of significant figures in each calculation.

1. Show the calculation of the mass of a 18.6 ml sample of freon with
density of 1.49 g/ml

2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5
ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g
2. D = M / V = 26..5 = 0.862 g/ml

Question 5
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.

,3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of
significant figures)

1. 3.0600 contains 5 significant figures.
2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)

Question 6
Click this link to access the Periodic Table. This may be helpful
throughout the exam.
Classify each of the following as an element, compound, solution or
heterogeneous mixture and explain your answer.
1. Coca cola
2. Calcium
3. Chili

1. Coca cola - is not on periodic table (not element) - no element names
(not compound)
appears to be one substance = Solution

2. Calcium - is on periodic table = Element

3. Chili - is not on periodic table (not element) - no element names (not
compound)
appears as more than one substance (meat, beans,
sauce) = Hetero Mix

Question 7
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

Classify each of the following as a chemical change or a physical change

1. Charcoal burns
2. Mixing cake batter with water

, 3. Baking the batter to a cake

1. Charcoal burns - burning always = chemical change
2. Mixing cake batter with water - mixing = physical change
3. Baking the batter to a cake - baking converts batter to new material
= chemical change

Question 8
Click this link to access the Periodic Table. This may be helpful throughout
the exam.

Show the full Nuclear symbol including any + or - charge (n), the
atomic number (y), the mass number (x) and the correct element
symbol (Z) for each element for which the protons, neutrons and
electrons are shown - symbol should appear as follows: xZy+/- n

31 protons, 39 neutrons, 28 electrons

31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)
= 70Ga31 +3

Question 9
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

Name each of the following chemical compounds. Be sure to name all
acids as acids (NOT for instance as binary compounds)

1. PF5

2. Al2(CO3)3

3. H2CrO4

1.
PF5 - binary molecular = phosphorus pentafluoride
2.
Al2(CO3)3 - nonbinary ionic = aluminum carbonate

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Exam (elaborations)

Chem 103 Module 1 to 6 Exam answers Portage learning latest complete update

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