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uitwerkingen Wiskunde B Getal & Ruimte vwo B h6 deel 2 $3.23   Add to cart

Exam (elaborations)

uitwerkingen Wiskunde B Getal & Ruimte vwo B h6 deel 2

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Uitwerkingen van H6 oefentoets!

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  • June 4, 2024
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Scorevoorstel oefentoets vwo B deel 2
Hoofdstuk 6 Differentiaalrekening

In deze toets zijn de vragen gelabeld met K, T of I.
K = kennisvraag, T = toepassingsvraag, I = inzichtvraag
De toets bestaat uit elf vragen met in totaal 57 punten.
Er zijn twee K-vragen met in totaal 2 punten, zeven T-vragen met in totaal 39 punten en
twee I-vragen met in totaal 16 punten.

OPGAVE 1 TOTAAL 2P
n −1
K a nx voor elke n van 1p
K b f ( x) = g ( x)  f ( x)  g ( x) = −1 1p

OPGAVE 2 TOTAAL 14P
4x −1 (2 x + 1)  4 − (4 x − 1)  4 x −8 x + 4 x + 4
2 2
T a f ( x) = geeft f ( x) = = 2p
2x +1
2
(2 x 2 + 1)2 (2 x 2 + 1)2
f ( x) = 0 geeft −8 x 2 + 4 x + 4 = 0 oftewel −2 x 2 + x + 1 = 0 met D = 9 en x = − 12  x = 1 2p




schets 1p
min. is f (− 12 ) = −2 en max. is f (1) = 1 2p
T b g ( x) = 121 x 4 + 12 x3 − 2 x 2 + 30 geeft g ( x) = 13 x3 + 1 12 x 2 − 4 x 1p
g ( x) = 13 x3 + 1 12 x 2 − 4 x geeft g ( x) = x 2 + 3 x − 4 1p
g ( x) = 0 oftewel x 2 + 3x − 4 = 0 geeft x = 1  x = −4 1p




uit de schets volgt dat er buigpunten zijn voor x = 1 en x = −4 1p
x = 1 geeft buigpunt (1, 28 127 ) 1p
y = ax + b met a = g (1) = −2 16 1p
(1, 28 127 ) op y = −2 16 x + b geeft y = −2 16 x + 30 34 1p



© NOORDHOFF UITGEVERS BV 2020 SCOREVOORSTEL OEFENTOETS VWO B DEEL 2 HOOFDSTUK 6 1

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