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MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024 Course Mathematics for Intermediate Phase teachers (MIP1501) Institution University Of South Africa (Unisa) Book Mathematics for Intermediate Teachers$2.58
MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024 Course Mathematics for Intermediate Phase teachers (MIP1501) Institution University Of South Africa (Unisa) Book Mathematics for Intermediate Teachers
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Course
Mathematics for Intermediate Phase teachers
Institution
University Of South Africa
Book
Mathematics for Intermediate Teachers
MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024
Course
Mathematics for Intermediate Phase teachers (MIP1501)
Institution
University Of South Africa (Unisa)
Book
Mathematics for Intermediate Teachers
Exam (elaborations) MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024 • Course • Mathematics for Intermediate Phase teachers (MIP1501) • Institution • University Of Sout...
Exam (elaborations) MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024 • Course • Mathematics for Intermediate Phase teachers (MIP1501) • Institution • University Of Sout...
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MIP1501 Assignment
3 (COMPLETE
ANSWERS) 2024
(792287) - DUE 22 July
2024 ;100% TRUSTED
workings,
explanations and
solutions.
ADMIN
[COMPANY NAME]
,Question 1 (26) 1.1. Solve and explain each step to grade 6
mathematics learners the following multiplication and division
calculations involving fractions. 1.1.1. 684÷ 612 (6) 1.1.2. 714× 418
(4) 1.1.3. 316× 624 (6) 1.1.4. 817÷ 124 (4) 1.2. Modelling refers to
the idea that learners build in their minds and play out with objects
or in picture form on paper sometimes to solve problems. Give and
explain at least three benefits that you may achieve in your primary
mathematics class by employing modelling. (6)
Question 1.1: Multiplication and Division of Fractions
When teaching Grade 6 learners to solve multiplication and division
problems involving fractions, it's crucial to break down each step
clearly and use visual aids where possible.
1.1.1: 68÷612\frac{6}{8} \div \frac{6}{12}86÷126
To divide fractions, we multiply by the reciprocal of the second
fraction.
1. Write the division problem: 68÷612\frac{6}{8} \div
\frac{6}{12}86÷126
2. Find the reciprocal of the second fraction: Reciprocal of
612\frac{6}{12}126 is 126\frac{12}{6}612
3. Change division to multiplication: 68×126\frac{6}{8} \times
\frac{12}{6}86×612
4. Multiply the fractions: 6×128×6\frac{6 \times 12}{8 \times
6}8×66×12
5. Simplify: 7248\frac{72}{48}4872
6. Reduce to simplest form: 72÷2448÷24=32\frac{72 \div
24}{48 \div 24} = \frac{3}{2}48÷2472÷24=23 or 1121
\frac{1}{2}121
Explanation to learners:
, • Division of fractions is done by multiplying the first fraction
by the reciprocal of the second fraction.
• Reciprocal means flipping the numerator and denominator.
• Simplifying fractions involves dividing both numerator and
denominator by their greatest common divisor.
1.1.2: 714×418\frac{7}{14} \times \frac{4}{18}147×184
To multiply fractions, we multiply the numerators and the
denominators.
1. Write the multiplication problem: 714×418\frac{7}{14}
\times \frac{4}{18}147×184
2. Multiply the numerators: 7×4=287 \times 4 = 287×4=28
3. Multiply the denominators: 14×18=25214 \times 18 =
25214×18=252
4. Write the fraction: 28252\frac{28}{252}25228
5. Simplify: 28÷28252÷28=19\frac{28 \div 28}{252 \div 28} =
\frac{1}{9}252÷2828÷28=91
Explanation to learners:
• Multiplying fractions is straightforward: multiply the top
numbers (numerators) and the bottom numbers (denominators).
• Simplify the resulting fraction by finding the greatest common
divisor of the numerator and the denominator.
1.1.3: 316×624\frac{3}{16} \times \frac{6}{24}163×246
Similar to the previous multiplication:
1. Write the multiplication problem: 316×624\frac{3}{16}
\times \frac{6}{24}163×246
2. Multiply the numerators: 3×6=183 \times 6 = 183×6=18
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