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Chapter Five LAWS OF MOTION

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Chapter Five LAWS OF MOTION

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  • June 23, 2024
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  • 2023/2024
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Chapter Five

LAWS OF MOTION




MCQ I
5.1 A ball is travelling with uniform translatory motion. This
means that
(a) it is at rest.
(b) the path can be a straight line or circular and the ball travels
with uniform speed.
(c) all parts of the ball have the same velocity (magnitude and
direction) and the velocity is constant.
(d) the centre of the ball moves with constant velocity and the
ball spins about its centre uniformly.

5.2 A metre scale is moving with uniform velocity. This implies
(a) the force acting on the scale is zero, but a torque about the
centre of mass can act on the scale.
(b) the force acting on the scale is zero and the torque acting
about centre of mass of the scale is also zero.




20/04/2018

, Exemplar Problems–Physics

(c) the total force acting on it need not be zero but the torque on it
is zero.
(d) neither the force nor the torque need to be zero.

5.3 A cricket ball of mass 150 g has an initial velocity u = (3ˆi + 4 ˆj) m s−1

and a final velocity v = − (3ˆi + 4ˆj) m s−1 after being hit. The change
in momentum (final momentum-initial momentum) is (in kg m s1)
(a) zero
(b) – (0.45ˆi + 0.6 ˆj)

(c) – (0.9ˆi + 1.2ˆj)

(d) – 5(ˆi + ˆj) .

5.4 In the previous problem (5.3), the magnitude of the momentum
transferred during the hit is
(a) Zero (b) 0.75 kg m s–1 (c) 1.5 kg m s–1 (d) 14 kg m s–1.
5.5 Conservation of momentum in a collision between particles can
be understood from
(a) conservation of energy.
(b) Newton’s first law only.
(c) Newton’s second law only.
(d) both Newton’s second and third law.
5.6 A hockey player is moving northward and suddenly turns westward
with the same speed to avoid an opponent. The force that acts on
the player is
(a) frictional force along westward.
(b) muscle force along southward.
(c) frictional force along south-west.
(d) muscle force along south-west.

5.7 A body of mass 2kg travels according to the law x (t ) = pt + qt 2 + rt 3

where p = 3 m s−1 , q = 4 m s−2 and r = 5 m s−3 .

The force acting on the body at t = 2 seconds is
(a) 136 N
(b) 134 N
(c) 158 N
(d) 68 N



30

20/04/2018

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