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Moderne wiskunde 11e editie 4 Havo wiskunde A Vaardigheden 2 uitwerkingen
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Havo 4wisA Vaardigheden 2 uitwerkingen
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Vaardigheden 2Pa$na 11ó
2 , I _1.2 , 5 _17 g1*? + rft=q# *
1a s'6 30 30 30 * + tf; = to{l = 11*
s , 7 _15 , 14_29 C 7 _Z_2r _20 _ 1
b 12 18 36',36 36 è 10 3-30 30-30
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z5- 35_,56 35_121
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è (;)'=; xlxl=fr
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rl-,r1_1-Z_21
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c -r3_el i 8^7'8"7-56's6-56-28
d r - 3 _ Z- 3 _ 6 _tr
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3a
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Patana117
4a P=l5a d s=7xz + 10x
b u= l5m e g= I\nz + 4n+ 5
c k=6t f w---a-6a2+4
5a 3(x+2)=3x+6 -7(0,5x- 2) -- -J,§v + 14
b 2x(x+72)=2"2*rO* e -+x(-tl"+e)=6x2-24x
5x(2x-3)=10x2-15x Í -x(x-8)=-x2+8x
6a t = -5a(3a- 8) = -15a2 + 40a
b k=-5a(3a-8)+ 4cP+20a
k=-15a2+40a+4a2+20a
k=-lla2+60a
2x(3x+5)+7x y=4x(5x-3)+6x
6x2+l}x+7x !=20x2-l2x+6x
6xz + L1x y=20x2-6x
x(xz+6x)-3x2 k= l2m(2- 4m) + 6m2 + 30m
x3+6x2-3xz k=24m- 48mz + 6m2 + 30m
x3 + 3x2 k=54m-42m2
v& O NoordhofÍ Uitgevers bv
, VAARDIGHEDEN 2
c=-4w(4w-4)+25w-35 r=200p-5p(1-p)+p2
c=-l6y?+76w+25w-35 r=200p-5p+5p'+p'
c=-16w2+4lw-35 r=195p+6p2
h = l,5a(6a- 18) - 4(2az + 5i1 d=74(2x-3)+ 5x(2x*3)
h=9a2-27a-Baz-20 d=28x-42+10x2-15x
h=a2-27a-20 d=l3x-42+70x2
8a Bij x = 0 hoorty = 2 enbij x = 2hoort y = $.
b Ahmed heeft de formule juist geschreven.
c Jodievindt y=3x+2.
d A: K=
6n+8
G: N_
0,6c - 1,8
a
2 J
x=L6t + z) tr=+(0,6c- 1,8)
K-3p+4 N=0,2c-0,6
-l6a + l0
B: o=
4
q=\grca+ rc)
Q= -4a + 2L
Pagina 118
ea $+ ? = #'o,aao d #"8=#=0,069
n t21+ +tr=el=6,095 e (?)^
", = rl= t,778
c 63- 5í=';= 0,958 i 25 x (+)3 =h=g,ozs
í0a Na afronding kom je op 1,55.
b A: (2+:x10)l(5x7)
B: 7^3 I (10 + 7)
C: (120 - 40 x 2 3) I (32 x 50 x 2,5)
D: (35 + (7 - 2 x 4,5)2) I (12 x 13 + 8 x 5,5)
c 0,91 ;20,18; -0,18 ; 0,20
11a -21-1101 I !
11t5t1t-1 5
b De top zit halverwe Ea x = 1 en x = 2, dus bij x = lL.
G De coördinaten van de top zijn (lL,-tïl
d Een goede instelling is bijvoorbeeld Ymin ='2 en Ymax = t2.
O Noordhoff Uitgevers bv ?3
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