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MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024 $2.60
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MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024

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Exam study book Teaching Mathematics of Dianne Siemon - ISBN: 9780195997897 (Guaranteed Success)

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  • July 19, 2024
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MIP1501
Assignment 3
(COMPLETE
ANSWERS) 2024
(792287) - DUE 22
July 2024

, MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024

(792287) - DUE 22 July 2024

Question 1 (26) 1.1. Solve and explain each step to grade

6 mathematics learners the following multiplication and

division calculations involving fractions.

1.1.1. 684÷ 612 (6)

1.1.2. 714× 418 (4)

1.1.3. 316× 624 (6)

1.1.4. 817÷ 124 (4)

1.2. Modelling refers to the idea that learners build in

their minds and play out with objects or in picture form

on paper sometimes to solve problems. Give and explain




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,at least three benefits that you may achieve in your

primary mathematics class by employing modelling. (6)

1.1 Solving Fractions

1.1.1. 684 ÷ 612

1. Simplify the fractions:

68÷612\frac{6}{8} \div \frac{6}{12}86÷126

2. Find the reciprocal of the divisor:

68×126\frac{6}{8} \times \frac{12}{6}86×612

3. Simplify the fractions before multiplying:

6÷68÷4×12÷66÷6=12×21\frac{6 \div 6}{8 \div 4}

\times \frac{12 \div 6}{6 \div 6} = \frac{1}{2} \times

\frac{2}{1}8÷46÷6×6÷612÷6=21×12




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, 4. Multiply the numerators and the denominators:

1×22×1=22=1\frac{1 \times 2}{2 \times 1} =

\frac{2}{2} = 12×11×2=22=1

Explanation: We started by simplifying the fractions, then

found the reciprocal of the divisor, simplified the

fractions further, and finally multiplied the fractions.

1.1.2. 714 × 418

1. Convert to improper fractions (if necessary):

714×418=294×3387 \frac{1}{4} \times 4 \frac{1}{8} =

\frac{29}{4} \times \frac{33}{8}741×481=429×833

2. Multiply the numerators and the denominators:

29×334×8\frac{29 \times 33}{4 \times 8}4×829×33




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