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ENSF 694 MIDTERM EXAM QUESTIONS AND ANSWERS 2024/2025 FULLY SOLVED 100%;UNIVERSITY OF CALGARY
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ENSF 694 MIDTERM EXAM QUESTIONS AND ANSWERS 2024/2025 FULLY SOLVED 100%;UNIVERSITY OF CALGARY
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2024ENSF 694 MIDTERM EXAM QUESTIONS AND ANSWERS 2024/2025 FULLY SOLVED 100%;UNIVERSITY OF CALGARY
ENSF 694
WISEMAN ENSF 694 MIDTERM EXAM QUESTIONS AND ANSWERS 2024/2025 FULLY SOLVED 100%;UNIVERSITY OF CALGARY
Multiple Choice Questions Section Select the best answer and indicate it by filling in the circles on the Scantron answer sheet. Answers on this exam booklet will
not be counted.
1.Consider the following code segment:
for (m = 1; m <= n; m++ ) for ( k = 1; k <= m; k++ )
for ( p = 1; p <= k; p++ )
x++;
Which one of the following equations are a better approximation of number line that will be executed in the code segment,
above:
a) 1/12 (n(n+1)(2n+1) + 3 n(n+1))
b) 1/12 ((n+1)(2n+1) + 3 n(n+1))
c) 1/6 (n(n+1)(2n+1) + 3 n(n+1))
d) 1/12 (n(n+1)(2n+1))
2.The following function calculates the Maximum Subsequence Sum of the numbers in an array that contains integer
numbers (possibly negative), using an iterative method.
int maxSumIterative (const A[], int N, int& left, int& right)
{
int maxSum = 0;
for( int i=0; i<N; i++)
for (int j = i; j < N; j++)
{
int thisSum = 0;
for (int k = i; k <= j; k++)
thisSum += A [k];
if( thisSum > maxSum )
{
maxSum = thisSum;
left = i;
right = j;
}
}
return maxSum;
}
3.What is the running time complexity, Big-O for this function?
a.O(N2)
b.O(N)
c.O(N3)
d.O(1)
4.Which one of the following statements are correct about three sort technique: Quick sort, Shell sort, and Bubble sort?
a.On average, Bubble sort is the slowest, Shell sort is fastest and Quick sort somewhere in the middle.
b.On average, Bubble sort is the slowest, Quick sort is fastest and Shell sort somewhere in the middle.
c.On average, Shell sort is the slowest, Quick sort is fastest and Shell sort somewhere in the middle.
5.The following function implements a binary-search on a sorted array:
int search(int L[], int low, int high, int x) {
if (high >= low) {
int mid = low + (high - low) / 2;
if (L[mid] == x)
return mid;
if (L[mid] > target)return search(L, low, mid - 1, x);
return search(L, mid + 1, high, tx);
}
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