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Summary - Unit 4 - Inorganic Chemistry and the Periodic Table (9CH0) $3.87   Add to cart

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Summary - Unit 4 - Inorganic Chemistry and the Periodic Table (9CH0)

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A summary of topic 4, organised so the notes are easy to understand. The notes are on slides, so they can be printed out and used as revision cards or posters, for revision on the go. The notes cross-reference the specification so it is easy to see where each bit of information has come from. They ...

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  • August 5, 2024
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Group 7 Test for halides (silver nitrate):
Reactivity ↓ down group (↑ shells = ↓ attraction) NaX + AgNO3 →AgX + NaNO3
MPT & BPT ↑ down group (↑ london forces) Ppts: AgCl = white & darkens in light
Electronegativity ↓ down group (↑ shells = ↓ attraction) AgBr = cream & darkens in light
Organic solubility ↑ down group (↑ london forces) AgI = yellow
Water solubility ↓ down group (↓ electronegativity) Ammonia solubility: AgCl = dissolves in conc & dil
Colours: (test for halogens) AgBr = dissolves in conc
Halogen At room temp In aq solution In organic solution AgI = doesn't dissolve
Reducing power:
F Pale yellow gas x x MX + H2SO4 → HX + MHSO4
Cl Pale green gas colourless colourless
- When heated w/ conc H2SO4 halides act as reducing agents (loose
e-, donate e- to another species)
Br Orange/brown liquid orange orange/red - X- loses an e- when it reduces H 2SO4
- Down group = easier to lose an e- due to ↑ radii & ↑ shielding ∴ I-
I Black solid brown pink/violet
ions most reactive
Redox reactions of halogens w/ halides - ∴ I- reduce H2SO4 further
- 2NaBr + Cl2 →2NaCl + Br2 (goes orange in aq & org solvent) Method = add halide + H2SO4 & observe gases leaving the tube.
Cl2 + 2Br- →2Cl- + Br2 Test for HX gases w/ ammonia (explained later)
- 2NaI + Cl2 →2NaCl + I2 (goes brown in aq, pink in org solvent) 1. Cl-
Cl2 + 2I- →2Cl- + I2 H+ + Cl- → HCl (HCl - white misty fumes, white smoke-y fumes w/ ammonia)
- 2NaI + Br2 →2NaBr + I2 (goes brown in aq, pink in org solvent) 2. Br-
Br2 + 2I- →2Br- + I2 H+ + Br- → HBr (HBr - white misty fumes, white smoke-y fumes w/ ammonia)
Disproportionation: H2SO4 + 2H+ + 2Br- → Br2 + SO2 + 2H2O (Br2 = orange fumes,
SO2 = colourless choking fumes)
1. Cl2 + water to kill bacteria
Cl2 (aq) + H2O(l) → HClO(aq) + HCl(aq) 3. I-
0 +1 -1 H+ + I- → HI (HI - white misty fumes, white smoke-y fumes w/ ammonia)

2. Bleach (NaClO) made from Cl2 + cold NaOH H2SO4 + 2H+ + 2I- → I2 + SO2 + 2H2O (I2 = orange fumes,
SO2 = colourless choking fumes)
Cl2 (aq) + 2NaOH(aq) → NaCl(aq) + NaClO(aq) + H 2O(l)
H2SO4 + 6H+ + 6I- → 3I2 + S + 4H2O (S = yellow solid)
0 -1 +1
H2SO4 + 8H+ + 8I- → 4I2 + H2S + 4H2O (H2S = colourless gas, egg smell)
Reactions w/ alkali’s:
Hydrogen halides:
3. Cold, strong alkalis Colourless, soluble gases due to polar H-X
X2 (aq) + 2MOH(aq) → MX(aq) + MXO(aq) + H 2O(l) W/ water, HX(g) + H2O(l) → H3O+(aq) + X-(aq)
0 -1 +1 W/ ammonia, HX(g) + NH3(g) → NH4X(aq) [salt]
4. Hot, strong alkalis HX test (used in reducing power test)
3X2 (aq) + 6MOH(aq) → 5MX(aq) + MXO 3(aq) + 3H2O(l) - Glass rod dipped in ammonia
0 -1 +5 - If it comes into contact w/ HX, white smoke from solid NH4X

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