D. 4x2 + 2 - ✔✔ANSW✔✔..The correct answer is (B) 4x2 + 6x + 2
. This is a multiplying binomials problem. Multiply the first term in the first binomial by
both terms in the second binomial:
4x2 + 4x
Then multiply the second term in the first binomial by each term in the second binomial:
2x + 2
Adding them all together you get:
4x2 + 4x + 2x + 2
4x2 + 6x + 2
2 − 8 ÷ (24 ÷ 2) =
A. -6
B. -¾
C. 1
D. 2 - ✔✔ANSW✔✔..The correct answer is (C) 1. Remember your order of operations:
Complete operations within parentheses first.
Calculate exponents.
Then multiply and divide in order from left to right.
Then add and subtract in order from left to right.
2 − 8 ÷ (24 ÷ 2) =
2 − 8 ÷ (16 ÷ 2) =
2−8÷8=
2−1=
, 1
3(x − 4) = 18, what is the value of x?
A. 3/2
B. 22/3
C. 6
D. 10 - ✔✔ANSW✔✔..The correct answer is (D) 10. Begin by dividing both sides by 3 to
open the parenthesis:
x−4=6
Add 4 to both sides to find x:
x = 10
A rectangle is cut in half to create two squares that each have an area of 25. What is
the perimeter of the original rectangle?
A. 20
B. 25
C. 30
D. 35 - ✔✔ANSW✔✔..Question 11 Explanation: The correct answer is (C) 30. The
formula to find the area of a square is side x side. If each square has an area of 25,
then the dimensions of the rectangle are 5 x 10. The perimeter is the sum of all the
sides, and would therefore be 5 + 10 + 5 + 10 = 30.
A scoutmaster is preparing his troop for their annual fishing expedition. He surveys each
of his scouts to find out how many fishing poles they own.
fishing pole owned
What is the mode of this data set?
A. 0
B. 1
C. 2
D. 3 - ✔✔ANSW✔✔..The correct answer is (A) 0. The mode of the data is the number
that appears the most often. In this case the largest number of scouts (7) own 0 fishing
poles.
Blair's average (arithmetic mean) on two physics tests is 7. What should Blair's score be
on the next test to have an overall average of 8 for all the tests?
A. 7
B. 8
C. 9
D. 10 - ✔✔ANSW✔✔..The correct answer is (D) 10. The arithmetic mean is defined as
the sum of the terms divided by the number of terms.
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