100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
BIOC 385 Modules 10-12 || with 100% Correct Answers. $11.49
Add to cart

Exam (elaborations)

BIOC 385 Modules 10-12 || with 100% Correct Answers.

 20 views  0 purchase
  • Course
  • BIOC 385 Modules 10-12
  • Institution
  • BIOC 385 Modules 10-12

Why do helicase and gyrase need to work together? correct answers Helicase unwinds DNA and gyrase relieves the torsional strain. Match the name of the DNA repair mechanism with the correct description. Functions with DNA replication to remove incorrect nucleotides from the nascent strand. ...

[Show more]

Preview 2 out of 11  pages

  • August 20, 2024
  • 11
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • BIOC 385 Modules 10-12
  • BIOC 385 Modules 10-12
avatar-seller
FullyFocus
BIOC 385 Modules 10-12 || with 100% Correct Answers.
Why do helicase and gyrase need to work together? correct answers Helicase unwinds DNA and
gyrase relieves the torsional strain.

Match the name of the DNA repair mechanism with the correct description.

Functions with DNA replication to remove incorrect nucleotides from the nascent strand.

Requires an endonuclease to remove an abasic nucleotide before DNA Pol I can replace a
portion of the strand.

Is needed to repair chemical damage in DNA effecting more than one nucleotide, such as
cyclobutane pyrimidine dimers.

Repairs nucleotide bases without requiring DNA ligase.

1.Mismatch repair
2.Base-excision repair
3.Nucleotide-excision repair
4.Direct repair correct answers __2__
Requires an endonuclease to remove an abasic nucleotide before DNA Pol I can replace a
portion of the strand.

__1__
Functions with DNA replication to remove incorrect nucleotides from the nascent strand.

__4__
Repairs nucleotide bases without requiring DNA ligase.

__3__
Is needed to repair chemical damage in DNA effecting more than one nucleotide, such as
cyclobutane pyrimidine dimers.

1.
Mismatch repair
2.
Base-excision repair
3.
Nucleotide-excision repair
4.
Direct repair

It has been estimated that as much as __________ % of the human genome is transcribed into
noncoding RNA, whereas __________ % of the E. coli genome is noncoding RNA. correct
answers 50; 10

, Which is often removed from eukaryotic mRNA before translation? correct answers introns

All DNA is synthesized in which direction? correct answers 5' -> 3'

What is the specific site on the E. coli genome where DNA replication can initiate? correct
answers oriC

If one parent has Lynch syndrome but the other does not, what is the likelihood that the child
will also have Lynch syndrome? correct answers 50%

What is a major function of prokaryotic DNA polymerase I besides replication? correct answers
checking for exonuclease activity

The two key elements of the oriC include correct answers three 13-bp repeats and four 9-bp
repeats with enriched A-T pairs.

What accounts for the high fidelity of DNA polymerization? Choose the ONE best answer.

Active site geometry but not nucleotide proofreading is important to the high fidelity of DNA
polymerization.

Active site geometry ensures that only correct sized nucleotide base pairs are formed, and 3' to 5'
proofreading removes incorrect nucleotides.

The most critical component of DNA polymerization is base stacking, which is more important
than hydrogen bonding at the replication fork.

The 5' to 3' exonuclease proofreading activity removes nucleotides, which provides a mechanism
to correct errors at the fork.

Nucleotide excision repair corrects all DNA replication errors, so DNA polymerase does not
need a proofreading activity. correct answers Active site geometry ensures that only correct sized
nucleotide base pairs are formed, and 3' to 5' proofreading removes incorrect nucleotides.

Both active site geometry and nucleotide proofreading are important to the high fidelity of DNA
polymerization.

How is the Ames test used to quantitate mutagenic potential of chemical compounds? Select the
TWO best answers.

The ratio of bacterial colonies to drug concentration (bc:dc) is used to calculate the mutagenic
index of a chemical compound; high bc:dc ratios means the drug functions as a growth factor for
the cells.

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller FullyFocus. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $11.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

49497 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$11.49
  • (0)
Add to cart
Added