0.1
0.3
0.2
Question
The frequency table below shows the ages of the students in a psychology lecture hall.
Complete the Relative Frequency column of the table. Enter answers as an unsimplified fraction.
4 Provide your answer below:
Age. 17 18 19 20 21 22
Frequency. 9 18 27 30 21 15
Relative Frequency
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Terms in this set (25)
Question AgeFrequency
The frequency table below shows the ages RelativeFrequency
of the students in a psychology lecture hall. 1799120=0.075181818120=0.15192727120=0.225203030120=0.25212121120=0.175221515120=0.1
Complete the Relative Frequency column of 25
the table. Enter answers as an unsimplified
fraction.
Provide your answer below:
Age. 17 18 19 20 21 22
Frequency. 9 18 27 30 21 15
Relative Frequency
Question Dividing each frequency by the total number of data values gives the relative
The relative frequencies for a set of data are frequency. Multiplying the relative frequency by the total number of data values gives
shown in the table below. the frequency.
ValueRelative The data value 1 occurs with relative frequency 0.15 in a data set of 40 values, the
Frequency10.1520.3030.4540.10 frequency of the data value 1 is0.15(40)=6.
If there are a total of 40 data values, with The data value 1 occurs 6 times.
what frequency does the data value 1 occur?
Provide your answer below:
, Given the relative frequency table below, Answer Explanation
which of the following is the corresponding Correct answer:
cumulative relative frequency table? Value:2 3 4 5.
Value cuulative relative frequency: 0.23 0.56 0.8 1
Relative Frequency Remember that a cumulative frequency table adds the relative frequencies for the
2 previous entries in the table. For example, the entry for the value 4 is0.23+0.33+0.24=0.8
0.23
3
0.33
4
0.24
5
0.2
Select the correct answer below:
Value
Cumulative relative frequency
20.2330.5640.851
Value
Cumulative relative frequency
20.2330.4640.851
Value
Cumulative relative frequency
20.3330.5640.851
Value
Cumulative relative frequency
20.1330.5640.851
Question Lower Class LimitUpper Class LimitFrequency1647124131871924125304
As the manager of a store, you wish to
determine the amount of money that people
who visit this store are willing to spend on
impulse buys on products placed near the
checkout register. You sample twenty
individuals and records their responses.
Construct a frequency table for grouped
data using five classes.
8,18,15,10,29,4,15,2,4,9,16,14,13,8,25,25,27,1,15,24
To determine the class width, use the formula:
Question Max Value−Min ValueNumber of Classes=1439−8386≈100.17
William wishes to view a frequency table for Since the data values are integers, round up to the next integer, 101. The minimum value,
grouped data using his monthly credit card 838, is the lower class limit of the first class. To find all other lower class limits, add the
statements for the last 20 months, shown class width, 101. For example, the second lower class limit would be: 838+101=939.
below. Construct the table for William using The upper class limit for each row is one less than the lower class limit from the
six classes. following row. For example, the upper class limit for the first row is 939−1=938. You can
1184, 1247, 945, 1124, 1034, 1352, 1025, 1439, also add the class width to one upper class limit to get the upper class limit for the next
1136, 1439, 1368, 1057, 1130, 1259, 1256, 1381, row.
838, 1342, 842, 1395 Lower Class LimitUpper Class
LimitFrequency838938293910393104011404114112411124213424134314436