100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
MAT3700 Assignment 3 (COMPLETE ANSWERS)2024 - DUE 28 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations $2.50   Add to cart

Exam (elaborations)

MAT3700 Assignment 3 (COMPLETE ANSWERS)2024 - DUE 28 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations

1 review
 15 views  2 purchases
  • Course
  • Institution
  • Book

MAT3700 Assignment 3 (COMPLETE ANSWERS)2024 - DUE 28 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations

Preview 2 out of 12  pages

  • August 22, 2024
  • 12
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers

1  review

review-writer-avatar

By: cmnhlapo • 2 months ago

The answer is froud

avatar-seller
MAT3700 Assignment
3 (COMPLETE
ANSWERS)2024 - DUE
28 August 2024 ; 100%
TRUSTED Complete,
trusted solutions and
explanations.




ADMIN
[COMPANY NAME]

, MAT3700 Assignment 3 (COMPLETE ANSWERS)2024 -
DUE 28 August 2024 ; 100% TRUSTED Complete, trusted
solutions and explanations.
QUESTION 1 If   =    3 6 1 4 B , find the eigenvalues of B.
(5)

To find the eigenvalues of the matrix BBB, you need to solve
the characteristic equation det(B−λI)=0\text{det}(B - \lambda I)
= 0det(B−λI)=0, where III is the identity matrix and λ\lambdaλ
represents the eigenvalues.
Given the matrix BBB:
B=(3614)B = \begin{pmatrix} 3 & 6 \\ 1 & 4
\end{pmatrix}B=(3164)
1. Form the matrix B−λIB - \lambda IB−λI:
B−λI=(3614)−λ(1001)=(3−λ614−λ)B - \lambda I =
\begin{pmatrix} 3 & 6 \\ 1 & 4 \end{pmatrix} - \lambda
\begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} =
\begin{pmatrix} 3 - \lambda & 6 \\ 1 & 4 - \lambda
\end{pmatrix}B−λI=(3164)−λ(1001)=(3−λ164−λ)
2. Find the determinant of B−λIB - \lambda IB−λI:
The determinant of B−λIB - \lambda IB−λI is:
det(B−λI)=det(3−λ614−λ)\text{det}(B - \lambda I) = \text{det}
\begin{pmatrix} 3 - \lambda & 6 \\ 1 & 4 - \lambda
\end{pmatrix}det(B−λI)=det(3−λ164−λ)
To calculate the determinant:

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller Jennifer2024. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $2.50. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

84866 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$2.50  2x  sold
  • (1)
  Add to cart