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Unit 2 PHYA2 - Mechanics, Materials and Waves
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,23rd September 2022 Mechanics
Vectors ,
Scalars ,
Resolving Equalibrium,
Free
1
-
Body Riagrams -
Reaction
1) Pick one RULES
-
to
analyze.
2) Draw
[
Fiction .
>
a simple representation
of the object
Thrust
I
3) Use a pencil and a rule
4)
weight Draw arrows to represent each
force acting
object
Y on .
5) make sure arrows show direction and
relative
-
size
of the
face .
Refinitions
:
·
Reaction
force exerted
by solid
surface which stops another body going into it.
-
a
:
the support
force exerted.
· Friction force acts solid
surfaces in It works in the direction opposite to the
along contact
-
.
motion.
Magnetic forces Force between
·
that
c rises
electrically charged particles because of their motion .
-
·
Tension Force the
stretching
exerted
by pulling against thing it
-
a stretched material which is
,
it apart
.
or
pulling
Weight This is
force
·
the due
-
to
gravity acting on the
body
.
W
mxg
=
Thrust Force
forward
·
exeted
by an
engine which
produces a propulsion .
-
·
Drag -
Frictional force of a fluid passing over a
surface of a
body.
, Free
Body
O
Riagrams
·
~
A sled being pulled up a will :
Reaction
*
[ ⑳ >
Normal reaction
Fro Full
force should be
weight perpendicular to
surface sled
this is
stationary
. Efriction
-
Fiction should Y
weight
be opposite to
directly
motion
Scalar
quantity with Vector
-- a
quantity
-o
size a with size +
direction .
·
Distance o
Displacement
Mass
· · Force
·
Temperature ·
velocity
·
Speed ·
Acceleration
Time
field
·
magnetic
·
strength
Charge
·
weight.
·
o Volume
.
·
Representing Vectors
> Size
of arrow-size
of vector
Direction
of =
arrow direction
of rector
Adding2 rectors :
Pythagoras
°
· Vectors & 90 =
·
Vectors not & 90 = Scale Drawing
.
, 26in September 2022 Vectors + Scalas
Adding Perpendicular Vectors :
1) Redraw the
diagram-tip to tail
2) Draw the resultant
from start to
finish
3) Calculate
magnitude of the resultant -
using Pythagoras
11) Calculate
angle-using Trigonometry
5) State where the
angle is measured
from
Questions :
B
1)
60km A
cory of
SOMCAHTOA
M
60hm
a) A -
> C b)
- + 202 tan" (8) : The ship travelled 632km
,
= 63
: 2km- 18 43"
.
noth-east .
=
=
18 .
430
Q5) zon
-or
M
a)
- x
·
7
> 3 W
. 8
10
3
TRIG
3 1 N
.
03 12 + .
= 37 N
:
:
with
a
forest
The
object travelled 3 7N
.
&
north-east 330
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