Summary
Samenvatting Oefeningen warmte- en stromingsleer
- Course
- Institution
Alle uitgewerkte werkcollege oefeningen van warmte- en stromingsleer. Ook een paar oefeningen van op de slides
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, W2-gesloten systeem- ideaal
gasmodel
Vraag
Zuiger-cilinder
PV = MRT - M
= =
130 .
0,07 = 0. 078
Leg
07m2 Polytroop PC 100 kPa 0 2968 393
V 0
.
=
=
. .
-
Pr = 130 kPa T =
100 ·
C
37
Tr =
120 C PV = MRT - V =
RT
070 0 2968 ,
·
,
.
100
P = 0, 086m
& PV" = PaVan
Pr --
1
=
----
I
M
. 3
1 = 1 ,
229
S
v
V-V
log (1 3) , =
n
log (1 229) ,
n =
1 ,
27
0006-130 0 07
= W Pak-per 10.0 , .
ly
.
=
- = 1, 05
1 -
M
1 27
1 -
,
Vaage 0 2070 285
MRT
V-T2 4 3m3
.
isothermpa
-
·
lucht
,
PV .
1
leg
=
=
2 4 ,
,
= 600 ke 150
P = 150 kPa -
In
T 12 C
.
In
=
zuiger
cilinder W MRT 2, 4 0 , 287 285 .
.
.
= .
A
Pe -
-of
-
= 272
,
14 f
I
Pr-t - -
g
I W =
MRT .
In ()
3 -
1
, 4 =
m()
V Vy
14
= =
E + V = 0, 32m
Vraag3 Pr = -12000 0, 42 + 600
.
6 d
V
S Plus =
Jav +
0,
42m
600
=
P2 -1200 0 12 +
M
-
=
b(v -M)
.
12m3 44
V 0
a
= -
.
=
+
L
P(V) = aV + 6 2 &
11/19
a -12000 KPa/m
8
8lf
=
-
=
,
6 = 600kPa
-
vraag 4
zuig-cilinder
m = 2
ky M
- OV
1
=
, 4
c
W :
R I Tot
Te 360k
P-100kPa-
=
9
0
T 300k
2961360-300
=
0
2
2
.
= ,
s
=
MRT = 1 77,
1 -
0 ,
4
I
= -88 8
b
·
189 29 ,
=
,
-
-
V = . 12
1 m
,Vraag-
5
&
zuiger-cilinder 13
·
lucht
m = 0, 15
kg sothermisch lytro isbaar
P = 2 MPa -
P2-Jookpa
naM Pa
-
Ve
T =
350 : o
S
1 2
V
,
V = RT
= 0 ,
01 Pal =
Py .
- V = 0, 01669m3
V 0 05 Was -PaVe
lf
= =
-34 4
, :
=
,
1 -
Wil =
MRT In .
1) = 37, 69
by
Ws P(V
by
=
-
Vs) = -7, 30
Wat 37 69- 34 4-7 38 4 03
lf
=
, , , = ,
6
Vraag
3m (constant)
=
V
Pr MRT-m 0
33
=
=
1 ,
Hz
P = 250 ka
T
Prese
= 550k
-
Tz = 350k
159 , 09 Pa
= Pr =
Qua = m .
G (TC -
T1)
= 0, 33 .
10 , 83 (350 .
550)
=
= 672 078 ,
f
Kraay7
yx5x7m3
V=
Ain-Quit Win-Wuit All 100 4x717 4
= e
+ = .
m ,
= 10000 ku . 287
0 .
283
(Ain-Quit + Win) At = m .
C (Te-Tu)
Wi = 100W
#10000 -
5000 + 100) At = 172 4 . 0, 718(20-10)
Quit 5000
by In
,
=
At = 830, 76 D
↑1 L ..
Pong = 100 kPa
w = 100 % = 0,
1 kla
& by R
= 10000
by /M = 2 , 78
5000 ty /M
Q 1 , 39
by /n
=
=
:
vraag
-
zuig-cilinder Qin-Quit + Win-Wuit = MCpAT
m = 15
leg -
60 + Win = 15 .
1 005
,
.
(77-25)
Tr =
25
Te = 77c Win = 045 .
9
by
Pr = Pc 300 kPa
59
=
=
Win 0, 235 h
Quit
=
=
Gol
Win =?
, Vags
Thermisch geisoleerde zuig-cilinde
V 1
= 0. 3 m2 CO2
P = 200 kPa
W = m .
Cp At
Tr 27 C
= o
=
m = 10
u = 110
At = 10 min = 600 s Win = 1 , 059 .
0, 846 . 300 =
311
b
Isoboar W v 1 At - 1 =
4 GA
=
= .
. ,
Vz = 0, 6 m3
Vraag
10
-
zuig-cilinder =
mRT-1 1915 ,
lucht Va m A
m = 3
kg = 2
, 583
2 S
P = 200 kPa
* &
le
Ain-Wint All
T = 27C
= =
m(Mz Mr) -
=
2674
P2 =
YookPa
1
=!
·
Rin Wint
Va =
2V1
= P(V -4) = 516
b >
W =
? = 10
1300k by 1 by
S [A17]
214 07
tabellen lucht
=
,
Magron = 933 , 33
l I leg
Yaag
11
lucht
m =
0
, 004 leg
1-2 : adiabatische compressie V =
RT = 0,
0034
P 100kPa
30057
=
=
U
T =
27c Te
Pr =
1MPa
2.3 : isbare warmte toevoer
Qin =
m .
(pAT = 0,
004
Qin 12
.
2 76
=
,
by
3-1 2, 76 0, 004
1, 005 .
(T3-579 2)
Warmteafvoer
= .
: .
P = G . V + C
G Tz = 1265 ,
77k
·
1
W =
Pe
(v -
v) =
PPMRT) = 237ly o >
powerpoint
u = 0 .
5m
yookpa
= 2
P =
M =
T =
27C
1 2A
·
=
At 5min
Win 1 1 At A2 by
=
=
= .
.
u = 120V
isaboar
AT
Aut =
2000
-
Quit + Win = M .
Cp .
Tz = AT
-
28 + 72 = 2 25 1 039
.
.
,
.
29 , 60 = Ja T1 -
Ta =
329 ,
6 k
↳ :
56 , 6 C
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