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Exam (elaborations) TEST BANK FOR Fundamentals of Physics 9th Edition By Resnick, Walker and Halliday (Instructor Solution Manual)

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  • Fundamentals Of Physics 9th Edition

1. Various geometric formulas are given in Appendix E. (a) Expressing the radius of the Earth as R = (6.37 × 106 m)(10−3 km m) = 6.37 × 103 km, its circumference is s = 2π R = 2π (6.37 × 103 km) = 4.00×104 km. (b) The surface area of Earth is ( )A = 4π R2 = 4π 6.37 × 103 km 2 = 5.10 × 1...

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  • August 27, 2024
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8/27/24, 3:18 PM Test bank for fundamentals of physics 9th edition by resnick w alker and hal…




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Chapter 1

1. Various geometric formulas are given in Appendix E.

(a) Expressing the radius of the Earth as

R 6.37 106 m 10 3
km m 6.37
3
10 km,

its circumference is s 2 R 2 (6.37 103 km) 4.00 104 km.

(b) The surface area of Earth is A 4 6.37 5.10 km2 .
4 R2 3
2 108
10 km

4
(c) The volume of Earth is V R3 6.37 103 km3.
4 3
km 1.08 1012
3 3

2. The conversion factors are: 1 gry 1/10 line , 1 line 1/12 i nch and 1 point
= 1/72 inch. The factors imply that

1 gry = (1/10)(1/12)(72 points) = 0.60 point.

Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 .

3. The metric prefixes (micro, pico, nano, …) are given for ready reference on the
inside front cover of the textbook (see also Table 1–2).

(a) Since 1 km = 1 103 m and 1 m = 1 106 m,

1km 103 m 103 m m.
6 m
m 10
109

The given measurement is 1.0 km (two significant figures), which implies our
result should be written as 1.0 109 m.
2
(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 10 m,

2
1cm = 10 m= 10 2m 10 6
m
m




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,8/27/24, 3:18 PM Test bank for fundamentals of physics 9th edition by resnick w alker and hal…
104 m.

We conclude that the fraction of one centimeter equal to 1.0 m is 1.0
4
10 . (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,


1




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2 CHAPTER 1



1.0 yd = 0.91m 106 m m.
5
m 9.1 10

4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch,
we obtain ⎞⎛ ⎞
0.80 cm⎛= 0.80 6 picas
⎜ 1 ⎟⎜ ⎟ 1.9 picas.
cm inch
2.54
⎝ cm ⎠ ⎝ 1 inch ⎠

(b) With 12 points = 1 pica, we
have
⎛ ⎞⎛ ⎞⎛
⎞ 1 inch 6 picas 12 points
0.80 cm = 0.80 cm
⎜ ⎟⎜ ⎟
23 points. ⎟⎜
2.54 cm 1 pica
1 inch ⎠ ⎝
⎝ ⎠⎝ ⎠


5. Given that 1 201.168 m , 1 rod and 1 chain 20.117 m , we
furlong 5.0292 m find
the relevant conversion factors to be
1 rod
1.0 furlong 201.168 m 40 rods,
(201.168 m ) 5.0292 m

and
1 chain
1.0 furlong 201.168 m 10 chains .
(201.168 m ) 20.117 m
Note the cancellation of m (meters), the unwanted unit. Using the given
conversion factors, we find

(a) the distance d in rods to be
40 rods
d 4.0 furlongs 4.0 furlongs 160 rods,
1 furlong

(b) and that distance in chains to be

10 chains
d 4.0 furlongs 4.0 furlongs 40 chains.
1 furlong

6. We make use of Table 1-6.

(a) We look at the first (“cahiz”) column: 1 fanega is equivalent to what amount of
cahiz? We note from the already completed part of the table that 1 cahiz equals a
dozen fanega.
Thus, 1 fanega =12 cahiz, or 8.33 10 2 cahiz. Similarly, “1 cahiz = 48 cuartilla”
1 (in the




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