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BIOC LAT 5 Exam Questions With Correct Answers
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BIOC LAT 5 Exam Questions With Correct Answers A restriction site is a.. - answerunique DNA sequence that is recognised by its specific restriction enzyme Alleles are... - answerdifferent versions of a gene or DNA region Jane is heterozygous for a mutant allele. The mutant allele is the result...

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  • August 28, 2024
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  • 2024/2025
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  • bioc lat 5 exam questions with correct answers

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©THEBRIGHT EXAM STUDY SOLUTIONS 8/21/2024 1:28 PM



BIOC LAT 5 Exam Questions With Correct
Answers

A restriction site is a.. - answer✔✔unique DNA sequence that is recognised by its specific
restriction enzyme

Alleles are... - answer✔✔different versions of a gene or DNA region
Jane is heterozygous for a mutant allele. The mutant allele is the result of a single DNA
nucleotide substitution. The DNA sequence of the mutant allele does not correspond to a
restriction site at the mutated site, while the DNA sequence of the normal wild-type allele does.


A 2400 bp PCR fragment was generated of Jane's gene region that contains the mutation. Her
genomic DNA was used as the PCR template. The DNA nucleotide substitution (the mutation) is
located 1200 bp into this PCR product and is recognised by the restriction enzyme EcoRI.


Half of the PCR product was left undigested while the other half was digested by EcoRI. Both
the undigested and EcoRI-digested samples were run on a DNA gel. The undigested DNA was
loaded into Lane 1 and the EcoRI-digested DNA was loaded into Lane 2 of the DNA agarose
gel.


What band(s) will be visualised in Lane 1 and Lane 2 on the DNA gel? - answer✔✔Lane 1: 2400
bp
Lane 2: 2400 bp and 1200 bp
Joe is heterozygous for a mutant allele. The mutant allele is the result of a single DNA nucleotide
substitution. The DNA sequence of the mutant allele does not correspond to a restriction site at
the mutated site, while the DNA sequence of the normal wild-type allele does.


A 1800 bp PCR fragment was generated of Joe's gene region that contains the mutation. His
genomic DNA was used as the PCR template. The restriction site of the normal wild-type allele
located 900 bp into this PCR product and is recognised by the restriction enzyme EcoRI.

, ©THEBRIGHT EXAM STUDY SOLUTIONS 8/21/2024 1:28 PM


Following an EcoRI restriction enzyme digest and DNA gel electrophoresis, what band(s) will be
visualised on the DNA gel? - answer✔✔1800 bp and 900 bp
The blood glucose reading given by the Accu-check Performa glucometer is based on an
enzymatic reaction generating: - answer✔✔a current

Which statement about the activation step in glycolysis in INCORRECT? - answer✔✔It
generates two ATP molecules during two substrate level phosphorylation steps, giving an overall
net gain of two ATPs
Jane is heterozygous for a mutant allele. The mutant allele is the result of a single DNA
nucleotide substitution. The DNA sequence of the normal wild-type allele does not correspond to
a restriction site at the mutated site, while the DNA sequence of the mutant allele does.


A 1500 bp PCR fragment was generated of Jane's gene region that contains the mutation. Her
genomic DNA was used as the PCR template. The DNA nucleotide substitution (the mutation) is
located 400 bp into this PCR product and is recognised by the restriction enzyme BamHI.


Half of the PCR product was left undigested while the other half was digested by BamHI. Both
the undigested and BamHI-digested samples were run on a DNA gel. The undigested DNA was
loaded into Lane 1 and the BamHI-digested DNA was loaded into Lane 2 of the DNA agarose
gel.


What band(s) will be visualised in Lane 1 and Lane 2 on the DNA gel? - answer✔✔Lane 1: 1500
bp
Lane 2: 1500 bp, 1100 bp and 400 bp
A high carbohydrate snack is consumed following a period of fasting. Which hormone would be
regulating carbohydrate metabolism following the snack? - answer✔✔insulin
Jane is heterozygous for a mutant allele. The mutant allele is the result of a single DNA
nucleotide substitution. The DNA sequence of the normal wild-type allele does not correspond to
a restriction site at the mutated site, while the DNA sequence of the mutant allele does.


A 1700 bp PCR fragment was generated of Jane's gene region that contains the mutation. Her
genomic DNA was used as the PCR template. The DNA nucleotide substitution (the mutation) is
located 500 bp into this PCR product and is recognised by the restriction enzyme BamHI.

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