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cop4610 exam 2 questions and correct answers graded A+ passed
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cop4610 exam 2 questions and correct answers graded A+ passed
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cop4610 exam 2T/F: In Xv6, each process's user stack is used for its system call handling. - correct answer ✔✔False, each
process's kernel stack is used for system call handling.
T/F: In Xv6, Trap frame is used to save the process's kernel machine state while performing context
switch. - correct answer ✔✔False, trap frame is used for passing user process data for kernel mode
handling of system calls.
T/F: For the first user process creation, the Xv6 kernel thread calls indium kernel routine to copy system
shell program (sh) to user-space. - correct answer ✔✔False, the first user process is in
it.
Xv6 kernel scheduler() routine executes as an extension to the current user process at timer interrupt. -
correct answer ✔✔False, the scheduler routine runs as its own thread, which is the first thread of xv6 at
boot time.
A 32-bit virtual address with 8KB page size has 2^19 page table entries in a single-level page table. -
correct answer ✔✔True, 32 bits per address with 2^13 addresses in a page calculates to 2^19 pages
Assume a system has a TLB hit ratio of 90%. TLB access takes 15ns, main memory access is 85ns, what is
the effective memory access time in ns with a single level page table for this system? - correct answer
✔✔108.5ns (.9*(15+85)+.1*(15+85+85))
Given the virtual (linear) address 0xAEF9 with a page size of 256 bytes, what is the page number? -
correct answer ✔✔0xAE, with 256bit pages the lowest magnitude two hex digits are the offset,
everything else is the page number.
The resulting value after evaluating the C expression ((0x801CB100 > 22) & (0x3FF)) - correct answer
✔✔0x200, The lowest magnitude 5 hex digits are right-shifted away, and 0x801 is left shifted another 2
times, leaving 0x200 & 0x3FFF, which equals 0x200.
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