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NABCEP Study Guide Exam With Correct Answers 2024
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NABCEP Study Guide Exam With Correct Answers 2024
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NABCEP Study Guide Exam With CorrectAnswers 2024
Balance .of .System .Compontents .- .correct .answer.Used .to .conduct, .distribute .and .control
.flow .of .power .in .the .system. .(Everything .besides .modules .and .inverters).
Power .Conditioning .Components .- .correct .answer.Inverters, .Charge .Controllers,
.Maximum .Power .Point .Trackers
Stand .Alone .PV .Systems .- .correct .answer.Operate .independently .of .other .electrical
.systems .(ie .the .Grid)
Interactive .PV .Systems .- .correct .answer.Operate .in .parallel .and .are .interconnected .and
.synchronized .with .the .electrical .grid.
Power .- .correct .answer.Power .is .the .RATE .of .transferring .energy. .Expressed .in .Watts. .
*Think .of .an .hourly .wage**
Energy .(definition) .- .correct .answer.The .TOTAL .amount .of .power .used .over .time
**Think .Total .Income**
Energy .(Equation) .- .correct .answer.Energy .(Wh) .= .Avg. .Power .(W) .x .Time .(hr)
1 .Megawatt .= .? .- .correct .answer.1,000,000 .Watts .
Power .Density .(Define) .- .correct .answer.Power .per .area .of .measurement .(Watts/Square
.Foot)
Power .Density .(Equation) .- .correct .answer.Power .Density .of .Module .= .Watts .of .Module ./
.Square .Footage .of .Module
Ex:
175 .W .module .that .is .14.4 .Square .Feet .has .power .density .of .12.2 .W/sf
Solar .Azimuth .Angle .- .correct .answer.Defines .the .direction .of .the .sun's .horizontal
.projection .relative .to .a .point .on .Earth.
,Solar .Altitude .Angle .- .correct .answer.Defines .the .Suns .elevation .above .the .horizon.
Zenith .Angle .- .correct .answer.Angle .of .the .sun .in .comparison .to .the .zenith .(90 .degrees)
Opposite .of .Altitude .Angle .(added .together .the .two .should .be .90)
Sun .Path .Diagram .- .correct .answer.A .graphical .representation .of .the .Sun's .altitude .and
.Azimuth .angles .over .a .given .day .of .the .year .(for .a .specific .latitude)
Solar .Noon .- .correct .answer.The .local .time .when .the .Sun .is .at .it's .highest .point .in .the .sky
.and .crossing .the .local .meridian .(line .of .Longitude).
It's .rarely .noon.
Best .way .to .find .it .is .to .find .the .projected .sunset .and .sunrise .time .and .then .determine .the
.midway .point.
Summer .Solstice .- .correct .answer.First .Day .of .Summer .(June .21st)
Winter .Solstice .- .correct .answer.First .Day .of .Winter .(December .21st)
Fall .Equinox .- .correct .answer.First .Day .of .Fall .(September .21st)
Spring .Equinox .- .correct .answer.First .Day .of .Spring .(March .21st)
Declination .- .correct .answer.The .angular .distance .of .a .point .north .or .south .of .the .celestial
.equator.
*The .sun .varies .+ .or .- .23.45 .degrees .throughout .the .year
Determine .Solar .Altitude .Angles .for .Region .- .correct .answer.Maximum .and .Minimum
.Solar .Altitude .Angles .are .determined .by .the .Winter .and .Summer .Solstice.
The .equation .is .as .follows:
90 .- .(Latitude) .+ .Solar .Declination
Example:
At .Latitude .40 .the .range .would .be .determined .as .follows
SUMMER .SOLSTICE
90 .- .40 .+ .23.45 .= .73.45
WINTER .SOLSTICE
90 .- .40 .+ .(-23.45) .= .26.55
, ALTITUDE .ANGLE .RANGE .FOR .40 .Deg .LAT
73.45 .to .26.55
Solar .Window .- .correct .answer.The .range .of .Sun .paths .for .a .specific .latitude .between
.Winter .and .Summer .solstices.
What .you .see .on .the .Suneye
Array .Azimuth .Angle .- .correct .answer.The .direction .an .array .surface .faces .based .on .a
.compass .heading .or .relative .to .due .south
Array .Tilt .Angle .- .correct .answer.The .array .tilt .angle .is .the .angle .between .the .array
.surface .and .the .horizontal .plane
Magnetic .Declination .- .correct .answer.The .angle .between .magnetic .north .and .the .true
.geographic .North .Pole.
Positive .Magnetic .Declination .- .correct .answer.When .Magnetic .North .is .East .of .true
.north.
Negative .Magnetic .Declination .- .correct .answer.When .Magnetic .North .is .West .of .true
.north.
Agonic .Line .- .correct .answer.Region .where .magnetic .declination .is .zero
Contour .Chart .- .correct .answer.Compares .the .effects .of .array .orientation .on .the .amount
.of .Solar .energy .received.
Peak .Sun .Hours .- .correct .answer.Average .daily .amount .of .solar .energy .received .on .a
.given .surface.
Equated .to .number .of .hours .that .the .solar .irradiance .would .need .to .be .at .peak .level .of .1
.kW/m2 .to .accumulate .the .total .amount .of .daily .energy .received.
Inter .Row .Spacing .- .correct .answer.D .= .3H
D .is .distance .between .rows
H .is .height .of .module
Array .Cooling .based .on .Module .Orientation .- .correct .answer.Landscape .orientation
.provides .better .cooling .than .Portrait .orientation
Standoff .Mounting .Systems .- .correct .answer.AKA .Flush .Mount. .The .mounting .system
.that .Dan .Whitson .uses
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