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BCH 403 Final Exam Questions Solved 100% Correct | Latest Update

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BCH 403 Final Exam Questions Solved 100% Correct | Latest Update

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  • September 13, 2024
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  • BCH 403
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KenAli
BCH 403 Final Exam Questions
Solved 100% Correct | Latest Update


The delta H contributions that lead to the formation of a lipid bilayer include Van
der wwals interactions and hydrogen bonding - Answer true



In the signal hypothesis, a defected signal peptidase would result in membrane
proteins that are instead produced in the cytoplasm - Answer false



Active primary transport requires ATP b/c otherwise, the delta G of the transport
would be positive - Answer True



To be inserted, the alpha helical integral membrane protein requires at least on
helix that is at least 20 residues long and is also amphipathic - Answer True



The glycerophospholipids of a membrane bilayer have been modified to contain
additional Double bonds. This change will likely lower the activation of adenylate
cyclase by a G-protein - Answer False


(PHOTO)

a newly discovered enzyme has two substrates. Substrate 1 is strongly nonpolar and
small. Substrate 2 is strongly nonpolar and large. The kcat/Km for the two enzymes were
discovered to be as follows:

,T or F: A biochemical reaction, without a catalyst or thermodynamic coupling, takes 50
years to reach a state of equilibrium. W/o more information, we cannot make a
determination on either the value of the Keq constant or the positive or negative
value of the DeltaG of the reaction - Answer False



T or F: Due to its small size, the amino acid glycine can be found in tight turns in
a protein structure - Answer True



T or F: The Delta G of a reaction is defined as the energy required to bring the
concentration of reactants and products to equal concentration - Answer False



T or F: One strength of NMR is that it can detect multiple conformations of proteins
and one of its limitations is that proteins must contain certain isotopes - Answer True



T or F: A single residue mutation to an enzyme decreases its rate constant by one half.
This means the reaction now occurs more slowly. - Answer True



T or F: The hydrophobic packing of non-polar residues is thermodynamically favorable
b/c of both the hydrophobic effect and a larger number of weak van der waals -
Answer True



T or F: The classic experiment in which the protein ribonuclease A is first denatured
and reduced, then refolded, was used to demonstrate the role of aromatic residues in
stabilizing covalent disulfide bonds - Answer False



T or F: One reason that we require myoglobin and hemoglobin to store and
transport oxygen is b/c oxygen itself has very poor solubility in water - Answer True



T or F: A mutation in myoglobin that changes the distal histidine into alanine will
result in a lower P50 - Answer False

, The stability of an alpha helix is partly due to hydrogen bonding that occurs between
carbonyl oxygen of one helix and the amino hydrogen of a neighboring alpha helix -
Answer False



Which of the following statements if true regarding the hydrophobic effect - Answer
Non-polar molecules are driven together in order to maximize the entropy of water



The peptide in question 17 is dissolved into a soln that has a pH of 6.5. Under
these conditions, the net charge of the peptide is - Answer +1


A glycine residue is disruptive to the stability of an alpha helix or a beta strand because -
Answer It's R group is too small to participate in stabilizing interactions with neighboring
R groups



With a pKA of 6.37, the carbonic acid/bicarbonate system serves to buffer changes
to the pH of blood. The acid dissociates as follows


H2CO3 + H20 ----> (DOUBLEARROW) HCO3- + H3O+



If a solution of .5 M carbonic acid is adjusted to a pH of 2.5, the primary form of
the buffer will be: - Answer H2CO3



Most non-polar residues are located on the interior of a protein fold, but are
occasionally found on surfaces where they can mediate protein interactions. The
molecular basis of a hypothetical infectious disease is that a bacterial protein interacts
with a human protein by sharing a non-polar surface. Your goal as a researcher is to find
a way to disrupt this interaction. Which of the following surface mutations are most
likely to disrupt the protein interaction? - Answer leucine-->glutamine

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