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BUS 310 Probability Summary

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This is a comprehensive and detailed summary on probability for Bus 310.

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Summary of probabilities

Event Probability
A
not A

A or B


A and B


A given B

Example 1: A jar contains black and white marbles. Two marbles are chosen without replacement.
The probability of selecting a black marble and then a white marble is 0.34, and the
probability of selecting a black marble on the first draw is 0.47. What is the probability of
selecting a white marble on the second draw, given that the first marble drawn was
black?
Solution: P(Black and White) 0.34
P(White|Black)= = =0.72=72%
P(Black) 0.47

Example 2: The probability that it is Friday and that a student is absent is 0.03. Since there are
5 school days in a week, the probability that it is Friday is 0.2. What is the
probability that a student is absent given that today is Friday?
Solution: P(Friday and Absent) 0.03
P(Absent|Friday)= = =0.15=15%
P(Friday) 0.2

Example 3: At Kennedy Middle School, the probability that a student takes Technology and
Spanish is 0.087. The probability that a student takes Technology is 0.68. What is
the probability that a student takes Spanish given that the student is taking
Technology?
Solution: P(Technology and Spanish) 0.087
P(Spanish|Technology) = = =0.13=13%
P(Technology) 0.68

Summary: The conditional probability of an event B in relationship to an event A is the
probability that event B occurs given that event A has already occurred. The
notation for conditional probability is P(B|A), read as the probability of B given
A. The formula for conditional probability is:




The Venn Diagram below illustrates P(A), P(B), and P(A and B). What two
sections would have to be divided to find P(B|A)? Answer

, Basic Rules of Probability
[return to top]



Definition:
P denotes a probability.
A, B and C are specific events.
P(A) is the probability that an event A will occur.

Rule for computing probability of equal likely events



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