MMSC490 Exam 2 Questions And Correct Answers Graded A+
Which eukaryotic DNA polymerase replicates the lagging strand in the 3ʹ to 5ʹ direction?
a. α
b. γ
c. δ
d. None of the above; the lagging strand is replicated in the 5ʹ to 3ʹ direction.
Answer d. None of the above; the lagging strand is replicated in the 5ʹ to 3ʹ direction.
DNA polymerases can synthesize DNA:
a. de novo, by catalyzing the polymerization of free dNTPs.
b. to complementary dNTPs by adding on a single-stranded DNA.
c. to a hydroxyl group at the end of a growing polynucleotide chain hydrogen bonded to
a strand of RNA.
d. by the addition of dNTPs to a hydroxyl group at the end of a growing polynucleotide
chain that is hydrogen-bonded to a strand of DNA. -Answer d. by the addition of dNTPs
to a hydroxyl group at the end of a growing polynucleotide chain that is
hydrogen-bonded to a strand of DNA.
In addition to DNA synthesis, DNA polymerase I possesses a second catalytic activity: it
can
a. synthesize short RNA sequences.
b. synthesize short polypeptide sequences.
c. remove RNA primers.
d. ligate short segments of DNA together. - Answer c. remove RNA primers.
What eukaryotic DNA polymerase replicates the leading strand in the 5ʹ to 3ʹ direction?
a. α
,b. ε
c. δ
d. γ - Answer b. ε
Free rotation of one cut DNA strand around one uncut strand is the primary function of:
a. topoisomerase I.
b. topoisomerase II.
c. DNA helicase.
d. DNA polymerase. - Answer a. topoisomerase I.
Topoisomerase II functions to:
a. unwind DNA tangles.
b. allow DNA to swivel and unwind.
c. allow daughter chr
d. all of the above - Answer d. all of the above
Autonomously replicating sequences are:
a. yeast plasmids.
b. yeast telomeres.
c. bacterial plasmids.
d. yeast origins of replication. - Answer d. yeast origins of replication.
Telomeres are the:
a. midpoints of chromosomes.
b. microtubule attachment points on chromosomes. c. end-sequences of chromosomes.
d. enzyme complexes that complete DNA replication. - Answer c. end-sequences of
chromosomes.
,Point mutations in DNA result from:
a. incorporation of incorrect bases during replication.
b. changes as a result of chemical exposure.
c. changes as a result of radiation exposure.
d. All of the above - Answer d. All of the above
The most common cause of skin cancer is damage to DNA by:
a. infrared light.
b. ultraviolet light.
c. γ radiation.
d. β particle radiation. - Answer b. ultraviolet light.
Pyrimidine dimers:
a. block DNA replication and transcription.
b. can be repaired by photoreactivation.
c. can be repaired by nucleotide-excision repair.
d. All of the above - Answer d. All of the above
Cultured cells from xeroderma pigmentosum patients were unable to carry out:
a. base-excision repair.
b. nucleotide-excision repair.
c. synthesis of melanin.
d. DNA synthesis. - Answer b. nucleotide-excision repair.
E. coli DNA polymerase V:
a. is induced in response to high temperatures.
, b. recognizes thymidine dimers and inserts nucleotides on the opposite strand.
c. has a low frequency of errors.
d. is activated during transcription. - Answer b. recognizes thymidine dimers and inserts
nucleotides on the opposite strand.
Site-specific recombination:
a. occurs in randomly occurring DNA sequences.
b. is mediated by proteins that recognize specific DNA target sequences.
c. leads to programmed cell death.
d. is also referred to as homologous recombination. - Answer b. is mediated by proteins
that recognize specific DNA target sequences.
d. prokaryotic cell division. - Answer c. development of immune-system cells.
The DNA sequence to which an RNA polymerase binds to initiate transcription of a gene
is called a(n):
a. enhancer.
b. promoter.
c. polymerase-binding element.
d. origin of transcription. - Answer b. promoter.
The regions of the DNA where RNA polymerase binds can be identified by:
a. restriction mapping.
b. PCR.
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