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UGRD-MATH 6103 Calculus 2 Midterm Exam/50 Questions and Answers 100% Correct; ACLC - Naga (AMA Computer Learning Center) $18.49   Add to cart

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UGRD-MATH 6103 Calculus 2 Midterm Exam/50 Questions and Answers 100% Correct; ACLC - Naga (AMA Computer Learning Center)

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  • UGRD-MATH 6103
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  • UGRD-MATH 6103

UGRD-MATH 6103 Calculus 2 Midterm Exam/50 Questions and Answers 100% Correct; ACLC - Naga (AMA Computer Learning Center) UGRD-MATH 6103 Calculus 2 Midterm Exam/50 Questions and Answers 100% Correct; ACLC - Naga (AMA Computer Learning Center)

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  • September 20, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • ugrd math 6103 calculus 2
  • UGRD-MATH 6103
  • UGRD-MATH 6103
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Wiseman
UGRD-MATH6103 Calculus 2
1. Home
2. My courses
3. UGRD-MATH6103-2026S
4. Week 7- 8: The Derivatives 1 & 2
5. Midterm Exam

Started on Wednesday, 28 April 2021, 11:06 AM
State Finished
Completed on Wednesday, 28 April 2021, 12:57 PM
Time taken 1 hour 51 mins
Marks 45.17/50.00
Grade 90.33 out of 100.00
Question 1
Correct
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Question text
Continuity of functions of one variable




Select one:
a.
f is continuous for all values of x.

b.
f is continuous at both x = 3 and x = -3

c.
f is continuous at x = 3, but it is not continuous at x = -3

, d.
f is not continuous at x = 3, but it is continuous at x = -3
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Question 2
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Question text
Compute limx→0x3−7xx3limx→0x3−7xx3


Select one:
a.
−∞−∞
b.
+∞+∞
c.
∞∞
d.
no correct answer
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Question 3
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Question text
Answer the following questions. Simplify your answers if necessary.
Differentiate y=5x2+sinxcosxy=5x2+sinxcosx.
Select one:

, a.
y′=10x+cos2x−sin2xy′=10x+cos2x−sin2x
b.
y′=10x−cos2x−sin2xy′=10x−cos2x−sin2x
c.
y′=10x+cos2x+sin2xy′=10x+cos2x+sin2x
d.
y′=−10x+cos2x−sin2xy′=−10x+cos2x−sin2x
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Question 4
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Question text
Functions as X approaches plus or minus infinity.
Compute limx→∞x5−x2−10limx→∞x5−x2−10.
Select one:
a.
0

b.
1

c.
does not exist

d.
-1
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Question 5
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Question text
Answer the following questions. Simplify your answers if necessary.
Differentiate y=sin2xcos2xy=sin2xcos2x.
Select one:
a.
y′=2sec2x−tanxy′=2sec2x−tanx
b.
y′=−2sec2xtanxy′=−2sec2xtanx
c.
y′=−2sec2x−tanxy′=−2sec2x−tanx
d.
y′=2sec2xtanxy′=2sec2xtanx
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Question 6
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Question text
Find the derivative of y=5.4xy=5.4x.
Fill in the missing numbers to get the correct answer.
Answer:
4
y' = 5ln (Answer



)4x


Question 7
Correct

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