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ETS major field test in biology questions and answers

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ETS major field test in biology questions and answers

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  • September 21, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • ETS MAJOR FIELD
  • ETS MAJOR FIELD
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millyphilip
ETS major field test in biology questions
and answers

Pyrimidine dimers formed in DNA due to UV radiation can be repaired by?

SOS repair
Double strand break repair
Mismatch repair
Photoreactivation repair (nucleotide excision repair)
Base excision repair - Answer -Photoreactivation repair (nucleotide excision repair)

Which of the following repair mechanisms uses methyl groups to distinguish between
parental and daughter strands?

Answers:
Mismatch repair
Photoreactivation repair (Nucleotide excision repair)
SOS repair
Double strand break repair
Base excision repair - Answer -Mismatch repair

Which of the following types of molecules is always found in virions?
Answers:
Protein
RNA
Lipid
DNA
Carbohydrate - Answer -Protein

A Barr body found within the female mammalian cell's nucleus is an example of ___
Answers:
Euchromatin
Polytene chromosome
Pseudogenes
Heterochromatin
Cistron - Answer -Heterochromatin

,In vertebrate genes, transcription regulatory regions that contain CpG islands are
inactivated by which CpG modification?
Answers:
Methylation
Ubiquitination
Acetylation
Phosphorylation
Myristoylation - Answer -Methylation

TATA-binding protein (TBP) is a key transcription factor in eukaryotes. A schematic
representation of the 240-amino acid TBP of yeast is shown in Fig. 1 below, with the
positions of 2 mutations indicated. The boxed area represents the evolutionarily
conserved C-terminal domain of TBP, and the shaded (dark) regions of this domain
represent two repeated elements involved in DNA binding. One mutation (P65S)
changes proline 65 to serine and the other I143N changes isoleucine 143 to
asparagine. Fig. 2 below represents autoradiographs of gels containing RNA transcripts
produced in extracts of wild type or mutant cells. Lanes 1-2 are from wild-type yeast
(WT), lanes 3-4 are from the I143N mutant and lanes 5-6 are from P65S mutant, as
indicated. Fig. 2A shows transcripts of a gene transcribed by RNA polymerase I (Pol I).
Fig. 2B shows transcripts of a gene transcribed by RNA polymerase II (Pol II). Fig. 2C
shows transcripts - Answer -Whether mutant transcription phenotypes are due to
perturbation of TBP function.

A set of genes from Bacillus subtilis that encode the proteins required for sporulation
have conserved DNA sequences -35 and -10 nucleotides before the site of transcript
initiation. However, the sequence at -35 is different from that seen in most other genes
from that species. Which of the following best explains this difference?
Answers:
Transcription of these genes is induced by cAMP
Translation of the mRNAs transcribed from these genes requires specific ribosomes
that recognize a modified Shine-Dalgarno sequence
A novel sigma factor is required for transcription initiation at these genes
The -35 sequence is the binding site for a repressor of transcription
The replication of these genes requires a specifically modified DNA polymerase. -
Answer -A novel sigma factor is required for transcription initiation at these genes

Which of the following repair mechanisms is often mutagenic?
Answers:
Mismatch repair
Photoreactivation repair (Nucleotide excision repair)
Base excision repair
SOS repair - Answer -SOS repair

The polytene chromosomes seen in Drosophila are
Answers:
Multiple copies of a single chromosome

, Produced by repeated rounds of DNA replication followed by nuclear division
Produced only after the completion of mitosis
Not carrying out transcription
smooth in appearance - Answer -Multiple copies of a single chromosome

A frameshift mutation is created when
Answers:
A codon's nucleotide sequence changes so that it calls for production of a different
amino acid than the original one
An initial mutation is reversed by a second mutation
A codon's nucleotide sequence changes so that instead of coding for a given amino
acid, it acts to terminate translation
A base pair is either inserted or deleted in a gene
A codon's nucleotide sequence changes but the amino acid it codes for does not
change. - Answer -A base pair is either inserted or deleted in a gene

Which of the following best explains how mutations in DNA can result in the expression
of a new phenotype?

Answers:
The polarity of tRNA becomes the opposite of that of DNA
A different polypeptide is produced
Eukaryotes and prokaryotes have similar ribosomes
The gene is now read in the 3' to 5' direction
Nucleic acids are methylated - Answer -A different polypeptide is produced

Based on the figure shown, the RNA primer can be found at
Answers:
C
D
E
A
B - Answer -A

In genetic engineering, bacteria are commonly used to produce mammalian proteins. In
these instances the cDNA that codes for the protein is used rather than the genomic
DNA. Which of the following provides the best explanation for doing this?
Answers:
It is easier to clone RNA than DNA
It is not possible to clone the entire coding region of the gene
It is easier to clone cDNA than genomic DNA of comparable size
Most eukaryotic genes have introns that cannot be removed in bacteria.
Most eukaryotic gene promoters do not function in bacteria - Answer -Most eukaryotic
genes have introns that cannot be removed in bacteria.

Based on the figure shown, the location of DNA with a free 3'-OH is

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