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NAEMSE FOUNDATIONS OF LEARNING (NCEE EXAM) ACTUAL EXAM QUESTIONS AND CORRECT ANSWERS|AGRADE

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NAEMSE FOUNDATIONS OF LEARNING (NCEE EXAM) ACTUAL EXAM QUESTIONS AND CORRECT ANSWERS|AGRADE

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  • September 30, 2024
  • 15
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • NAEMSE FOUNDATIONS OF LEARNING (NCEE
  • NAEMSE FOUNDATIONS OF LEARNING (NCEE
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NAEMSE FOUNDATIONS OF LEARNING (NCEE
EXAM) 2024-2025 ACTUAL EXAM QUESTIONS
AND CORRECT ANSWERS|AGRADE

Terms in this set (39)

The main assumptions of the Rescorla-Wagner model
are:
(1) surprise necessary for learning
Describe main assumptions (2) surprise determines how much is learned on any
of the Rescorla-Wagner given episode
model of conditioning. (3) as total knowledge increases, material becomes less
(a) What produces learning 'surprising'
in this model? (i.e., what (4) when total knowledge = maximum (material
causes learning to occur). completely learned), material no longer surprising ->
(b) What causes learning to learning stops
stop according to the
model? a) when what you get != what you expect means
(c) What is relationship SURPRISE
between theoretical b) when maximum association is achieved/no more
increments in associative surprise
strength across training c) early CS-US trials: person still learning CS predicts US
trials and the shape of the (US is still 'surprising") each CS-US trial produces some
empirically observed learning
learning curve? (in other later (asymptote): person knows CS perfectly predicts
words, what aspects of US
observed data seem to fit (US no longer surprising) additional CS-US trials
with assumptions of the produce
model for initial acquisition no new learning
of a behavior).
There is a relatively steep learning curve and then a
plateau which mirrors that of observed learning behavior
in animals

, ΔV = k(λ-v) Vcurr = ΔV + Vprev
Write out the Rescorla-
Wagner equation and ΔV is the amount learned on each trial
define the variables within k is the salience of the CS+ US
it. λ is the maximum possible association we can make
v is curr total strength of learning at the end of prev trial

V=0 λ=.7 k=.6 Trial 6


Trial 1: ΔV = .6(.7-0) v = .42
Trial 2: ΔV = .6(.7-.42) v = .42
+.17 = .59
Trial 3: ΔV = .6(.7-.59) v =.59
+ .07 =.66
Trial 4: ΔV = .6(.7-.66) v =.66
+ .02 =.68
Trial 5: ΔV = .6(.7-.68) v =.68
+ .01 = .69
Trial 6: ΔV = .6(.7-.69) v =.69
+ .01 = .70
Trial 7: ΔV = .6(.7-.70) v =.70
+ .00 = .70


When did learning last
occur?

In blocking, the presence of an established CS interferes
with conditioning of a new CS.


What is the phenomenon Example: Suppose a light is conditioned as a CS for
known as blocking? salivation and is then paired with a tone to create a
compound stimulus. Because the light is already
preconditioned, little or no association will be made to
the tone.

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