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uitgewerkte oefeningen celcultuur

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oefeningen uitgewerkt, moet je kunnen op het examen

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  • October 8, 2024
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  • 2023/2024
  • Exam (elaborations)
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Oefeningen Verdunningen – practicum celcultuur en
immunochemie ‘23
Naam student: femke van nimmen
Rolnummer: S0213580

1) Bereken de benodigde volumes celsuspensie en diluent die je in totaal nodig hebt
om een 24-well plaat te vullen met 1,75x10 5 cellen/well, indien je 2 mL celsuspensie
ter beschikking hebt met 0,9 x10 8 cellen en het uiteindelijke volume van 1 well 350
L is?


Gegeven:
Wellplaat: 24 1,75*105 cellen/well


Oplossing:
Stap 1: aantal cellen
24* 1,75*105 cellen/well = 4200000 cellen

Stap 2: concentratie bij 3mL
0,9* 108 cellen/ 2mL = 45 * 106 cellen/ mL

Stap 3: V bij celsuspensie
4200000 cellen/ 45 * 106 cellen/ mL = 0,09333 mL

Stap 4: v diluent

24 well-plaat * 350 L (= 0,350 mL) = 8,4 mL
8,4 mL - 0,09333 mL = 8,30667 mL

Dus: we hebben 0,09333 mL celsuspensie nodig en 8,30667 van het volume diluent.


2) Beschrijf volledig hoe je een antigenoplossing met concentratie 0,2 mg/mL, 2000 L
beschikbaar moet verdunnen, indien je een nieuwe oplossing wil bekomen van 3 mL
met concentratie 32 g/mL?

Gegeven:
V1= 2000 μL C1= 0,2 mg/mL
= 200 μg/ mL
V2= 3mL C2= 32 μg/mL
= 3*106 μL

Oplossing:
Stap 1: eindmassa:
V2 * C2 => (3*106 μL) * 32 μg/mL = 96* 106 μL

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