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WGU 191 Chapter 7 and 8 on Virtual and Main Memory Exam Review Questions and A Level Marking Scheme Latest 2024/2025 $10.49   Add to cart

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WGU 191 Chapter 7 and 8 on Virtual and Main Memory Exam Review Questions and A Level Marking Scheme Latest 2024/2025

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  • Course
  • WGU C191
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  • WGU C191

WGU 191 Chapter 7 and 8 on Virtual and Main Memory Exam Review Questions and A Level Marking Scheme Latest 2024/2025 Interrupt driven - correct answer When the CPU does not poll the control bit, but rather gets an interrupt signal Buddy-system/power-of-2-allocator - correct answer Allocates m...

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  • October 15, 2024
  • 8
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • WGU C191
  • WGU C191
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KieranKent55
WGU 191 Chapter 7 and 8 on Virtual and
Main Memory Exam Review Questions
and A Level Marking Scheme Latest
2024/2025

Interrupt driven - correct answer When the CPU does not poll the control bit, but rather
gets an interrupt signal


Buddy-system/power-of-2-allocator - correct answer Allocates memory from a fixed-
size segment consisting of physically contiguous pages via units sized as a power of
2(or rounded up to the next as needed).


Buddy - correct answer When a larger memory block is divided into a smaller part to
satisfy the request. Two smaller parts of a block are of equal size and called buddies.
Note that this may cause fragmentation (i.e. if a 11kb block is needed but 16kb block is
allocated(b/c it's a power of 2))


Coalescing - correct answer If needed split blocks of memory (buddies) can come
together to form larger segments of memory if needed


Slab allocation of kernel memory - correct answer A slab is one or more physically
contiguous pages


Cache allocation of kernel memory - correct answer Consists of one or more slabs.
There is a single cache for each unique kernel data structure


Objects - correct answer Objects populate the cache(multiple slabs) of the kernel data
structure that the cache represents (e.g. semaphore cache has semaphore objects)


Prepaging - correct answer Bringing into memory at one time all pages that will be
needed

, Resolution - correct answer Isolating the memory that is actually needed through a
smaller page size


TLB Reach - correct answer The amount of memory accessible from the translation
lookaside buffer. Found by the number of entries multiplied by the page size


page locking/pinning - correct answer ensures a process stays in main memory and is
exempt from paging.


Clustering - correct answer Handling a page fault by bringing in not only the faulting
page, but also several pages following the faulting page.


Working set minimum - correct answer The minimum number of pages the process is
guaranteed to have in memory up to its working set maximum


Automatic working set trimming - correct answer When free memory falls below a
threshold, the virtual memory will use this to restore the memory above the threshold


Pageout - correct answer when pages are written to disk


Priority paging - correct answer Distinguishing pages that have been allocated to
processes versus pages that have been allocated to regular files




True or False? A program does not need to be stored in memory in its entirety. - correct
answer True


True or False? A physical address space is at least as large as a virtual address space.
- correct answer False

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