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CHEM 219 EXAM 1 QUESTIONS AND ANSWERS GRADED A+

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CHEM 219 EXAM 1 QUESTIONS AND ANSWERS GRADED A+ On a piece of scratch paper, write out the Lewis Dot Diagram for each of the indicated elements and determine the following for each: a) The number of Lone Pairs the atom possesses in its valence shell. b) The number of Unpaired Electrons the ato...

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  • October 16, 2024
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EMILLECT 2024/2025 ACADEMIC YEAR ©2024 EMILLECT. ALL RIGHTS RESERVED FIRST PUBLISH OCTOBER, 2024




CHEM 219 EXAM 1 QUESTIONS AND
ANSWERS GRADED A+

On a piece of scratch paper, write out the Lewis Dot Diagram for each of the indicated elements

and determine the following for each:


a) The number of Lone Pairs the atom possesses in its valence shell.


b) The number of Unpaired Electrons the atom possesses in its valence shell.


c) The number of bonds the atom will form.




Oxygen


Carbon


Hydrogen


Nitrogen - Answer✔✔-Oxygen - a) 2 b) 2 c) 2


Carbon - a) 0 b) 4 c) 4


Hydrogen- a) 0 b) 1 c) 1


Nitrogen - a) 1 b) 3 c) 3




Page 1/7

, EMILLECT 2024/2025 ACADEMIC YEAR ©2024 EMILLECT. ALL RIGHTS RESERVED FIRST PUBLISH OCTOBER, 2024


Classify the bonding between the given pairs of atoms as ionic, covalent, or polar covalent. Use

the table of electronegativities shown below to help with the classification.


a. Br and Br


b. K and Cl


c. P and Cl


d. C and O


e. Na and Br - Answer✔✔-a. Br-Br: Electronegativity difference () = 0 = COVALENT (or pure

covalent)


b. K-Cl: () = 2.2 = IONIC


c. P-Cl: ()= 0.9 = POLAR COVALENT


d. C-O: ()= 1.0 = POLAR COVALENT


e. Na-Br: () = 1.8 = POLAR COVALENT


Define the term constitutional isomer. - Answer✔✔-Two (or more) different chemical

compounds with the same molecular formula but different connectivity between the atoms in

their structural formulae.


Explain (using specific evidence) what makes the following two compounds constitutional

isomers of one another: - Answer✔✔-Both compounds have a MF of C3H6O - same MF.


Compound "a" has a 3-carbon chain with a C=O in the middle. No H atom connected to C of

C=O.
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