Exam (elaborations)

Solutions for Chemical Engineering Computation with MATLAB® 2nd Edition by Yeo (All Chapters included)

1 purchase

Course
Computers

Institution
Computers

Complete Solutions Manual for Chemical Engineering Computation with MATLAB® 2nd Edition by Yeong Koo Yeo ; ISBN13: 9780367547820......There is no Solution for Ch 1. MATLAB Programs and Lab slides are included...1. Introduction to MATLAB® 2. Numerical Methods with MATLAB® 3. Physical Properties...

[Show more]

Preview 4 out of 218 pages

View example

Uploaded on October 17, 2024
Number of pages 218
Written in 2024/2025
Type Exam (elaborations)
Contains Questions & answers

solutions
manual
answer guide
matlab programs
lab slides
chemical engineering
computation with matlab
2nd edition
yeo
9780367547820
solutions manual
2e

Institution Computers
Course Computers

mizhouubcca Member since 1 year 1080 documents sold

133

$29.49

Add to cart

Add to wishlist

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached

Chemical Engineering Computation
with MATLAB® 2nd Edition by
Yeong Koo Yeo

Complete Chapter Solutions Manual
are included (Ch 1 to 11)

** Immediate Download
** Swift Response
** All Chapters included
** MATLAB Programs
** Lecture Slides

,Table of Contents are given below

1. Introduction to MATLAB®

2. Numerical Methods with MATLAB®

3. Physical Properties

4. Thermodynamics

5. Fluid Mechanics

6. Chemical Reaction Engineering

7. Mass Transfer

8. Heat Transfer

9. Process Control

10. Optimization

11. Computational Intelligence

,Chapter 2 Numerical Methods with MATLAB

Linear Systems
2.1 In the photosynthesis reaction, water reacts with carbon dioxide to give glucose and oxygen. This
reaction can be expressed as
𝑥1 𝐶𝑂2 + 𝑥2 𝐻2 𝑂 → 𝑥3 𝑂2 + 𝑥4 𝐶6 𝐻12 𝑂6
Determine the values of coefficients 𝑥1 , 𝑥2 , 𝑥3 , and 𝑥4 to balance the equation. Is it possible to
determine these values? If not, under what conditions can the solutions be found?

2.1(Solution)
Carbon balance: 𝑥1 = 6𝑥4 , oxygen balance: 2𝑥1 + 𝑥2 = 2𝑥3 + 6𝑥4 , hydrogen balance: 2𝑥2 = 12𝑥4 .
Rearrangement of these equations gives
𝑥1
1 0 0 −6 𝑥 0
2
[2 1 −2 −6 ] [𝑥 ] = [0]
3
0 2 0 −12 𝑥 0
4
We can use the backslash operator to get the solution:

>> x = A\b
x=
0
0
0
0

The given equations can be rewritten as
𝑥1 − 6𝑥4 = 0, 𝑥2 − 6𝑥4 = 0, 𝑥3 − 6𝑥4 = 0 ⇒ 𝑥1 = 6𝑥4 , 𝑥2 = 6𝑥4 , 𝑥3 = 6𝑥4
Thus if we set 𝑥4 = 1, we have 𝑥1 = 𝑥2 = 𝑥3 = 6.

2.2 Four reactors are connected by pipes where directions of flow are depicted by means of arrows as
shown in Figure P2.218. The flow rate of the key component is given by the volumetric flow rate
𝑄 (𝑙𝑖𝑡𝑒𝑟/𝑠𝑒𝑐) multiplied by the concentration 𝐶 (𝑔/𝑙𝑖𝑡𝑒𝑟) of the component. The incoming flow rate is
assumed to be equal to the outgoing rate. Using the flow rates given below, calculate the concentration at
each reactor:
𝑄13 = 75 𝑙𝑖𝑡𝑒𝑟 ⁄𝑠𝑒𝑐 , 𝑄24 = 20 𝑙𝑖𝑡𝑒𝑟 ⁄𝑠𝑒𝑐 , 𝑄33 = 60 𝑙𝑖𝑡𝑒𝑟 ⁄𝑠𝑒𝑐 ,
𝑄21 = 25 𝑙𝑖𝑡𝑒𝑟 ⁄𝑠𝑒𝑐 , 𝑄32 = 45 𝑙𝑖𝑡𝑒𝑟 ⁄𝑠𝑒𝑐 , 𝑄43 = 30 𝑙𝑖𝑡𝑒𝑟 ⁄𝑠𝑒𝑐

FIGURE P2.2

2.2(Solution)
Material balance for each reactor can be expressed as follows:
Reactor 1: 350 + 𝑄21 𝐶2 = 𝑄13 𝐶1 ⇒ 350 + 25𝐶2 = 75𝐶1 ⇒ 75𝐶1 − 25𝐶2 = 350
Reactor 2: 𝑄32 𝐶3 = 𝑄21 𝐶2 + 𝑄24 𝐶2 ⇒ 45𝐶3 = 25𝐶2 + 20𝐶2 ⇒ 45𝐶3 − 45𝐶2 = 0

, Reactor 3:
𝑄13 𝐶1 + 𝑄43 𝐶4 = 𝑄32 𝐶3 + 𝑄33 𝐶3 ⇒ 75𝐶1 + 30𝐶4 = 45𝐶3 + 60𝐶3 ⇒ 75𝐶1 + 30𝐶4 − 105𝐶3 = 0
Reactor 4: 150 + 𝑄24 𝐶2 = 𝑄43 𝐶4 ⇒ 150 + 20𝐶2 = 30𝐶4 ⇒ 30𝐶4 − 20𝐶2 = 150
These equations can be rearranged as
75𝐶1 − 25𝐶2 = 350, −45𝐶2 + 45𝐶3 = 0, 75𝐶1 − 105𝐶3 + 30𝐶4 = 0, −20𝐶2 + 30𝐶4 = 150
The following commands produce desired outputs:

>> A = [75 -25 0 0;0 -45 45 0;75 0 -105 30;0 -20 0 30]; b = [350 0 0 150]'; C = A\b
C=
7.4444
8.3333
8.3333
10.5556

2.3 Paraxylene, styrene, toluene and benzene are to be separated with the array of distillation columns
shown in Figure P2.3.19 Determine the molar flow rates (𝑘𝑔𝑚𝑜𝑙/𝑚𝑖𝑛) of 𝐷1 , 𝐷2 , 𝐵1 , and 𝐵2 .

FIGURE P2.3

2.3(Solution)
Material balance for each component is given by:
Xylene: 0.07𝐷1 + 0.18𝐵1 + 0.15𝐷2 + 0.24𝐵2 = 0.15 × 80 = 12
Styrene : 0.04𝐷1 + 0.24𝐵1 + 0.1𝐷2 + 0.65𝐵2 = 0.25 × 80 = 20
Toluene : 0.54𝐷1 + 0.42𝐵1 + 0.54𝐷2 + 0.1𝐵2 = 0.4 × 80 = 32
Benzene : 0.35𝐷1 + 0.16𝐵1 + 0.21𝐷2 + 0.01𝐵2 = 0.2 × 80 = 16
These equations can be rearranged as 𝐴𝑥 = 𝑏, which can be solved by using the backslash operator:

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller mizhouubcca. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $29.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

69411 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 15 years now

Start selling

Seller

Summary ·

Exam (elaborations)

Solutions for Chemical Engineering Computation with MATLAB® 2nd Edition by Yeo (All Chapters included)

Document information

Subjects

Written for