RSCR242 - Exam 1 Pilbeam CH1-5 Questions and Correct Answers the Latest Update and Recommended Version
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Course
RSCR242
Institution
RSCR242
Calculate the tubing compliance (CT) when the measured volume is 150 mL and the static
pressure is 53 cm H2O.
a. 0.003 mL/cm H2O
b. 0.35 cm H2O/mL
c. 2.8 mL/cm H2O
d. 7.95cm H2O/mL
→ C 2.8 mL/cm H2O
→ Calculate tubing compliance (CT) by dividing measured volume by measured static
pres...
RSCR242 - Exam 2 Pilbeam CH6-
Questions and Correct Answers the Latest
Update and Recommended Version
1. Calculate the tubing compliance (CT) when the measured volume is 150 mL and the static
pressure is 53 cm H2O.
a. 0.003 mL/cm H2O
b. 0.35 cm H2O/mL
c. 2.8 mL/cm H2O
d. 7.95cm H2O/mL
→ C 2.8 mL/cm H2O
→ Calculate tubing compliance (CT) by dividing measured volume by measured static
pressure.
2. When initially setting up a ventilator the plateau pressure (PPlateau) is measured at 47 cm
H2O with a set volume of 100 mL. After applying the ventilator to the patient, the average
peak pressure reached during volume delivery is 28 cm H2O. How much volume is lost in the
ventilator tubing?
a. 13 mL
b. 60 mL
c. 147 mL
d. 168 mL
→ B 60 mL
→ Calculate tubing compliance (CT) by dividing measured volume by measured static
pressure. The amount of volume lost to the circuit equals the pressure reached during a
tidal volume (VT) delivery multiplied by the CT factor.
6. Calculate the inspiratory time (TI) when a ventilator is set at a tidal volume (VT) of 500 mL
and a constant flow rate of 30 L/min.
a. 0.6 second
b. 1 second
c. 1.5 seconds
d. 1.7 seconds
→ B 1 second
→ TI = VT/VE (convert L/min to L/sec)
7. Calculate the inspiratory to expiratory (I:E) ratio when the inspiratory time is 0.5 seconds
and the respiratory rate is 30 bpm.
a. 1:3
b. 1:4
c. 4:1
d. 3:1
→ A 1:3
→ TCT = 60 sec/f, TCT - TI =TE, TI:TE = 1:X 0.5/0.5 = 1.5/0.5
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