Exam (elaborations)
Handboek oefeningen D'haeseleer William
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Belangrijkste oefeningen D'haeseleer William. Goede samenvatting voor tijdens het open boek examen.
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Handboek oefeningen W.DH.Hoofdstuk 1: Introduction and first law of thermodynamica
- Reversibele arbeid
(Slide 32, Hbp 12)
v2
W = −m ∫ p . dv
v1
- Reversibele arbeid
(Slide 34, Hbp 13)
Work done by the fluid =
arbeid geleverd door systeem
(= negatief). Dus in wijzerzin
berekenen (3-1-2)
W = W12 + W23
v2
met W = − ∫ p . dv
v1
- Gesloten systeem
(Slide 36, Hbp 16)
∑Q + ∑W = 0, voor gesloten systeem
∑dQ + ∑dW = 0
∑dQ = …m kW met m = steam flow rate
- 1ste wet Thermodynamica
(slide 39, hbp 18)
∆U = u2 –u1 = Q + W
1
, ∆U = u2 –u1 = Q + W
- Stationaire energievergelijking
(stroomsnelheid cte)
(Slide 43, Hbp 21)
c 22 c 21
-
( ) (
ḿ h 2+ − ḿ h1+ =Q́+ Ẃ
2 2 )
- Arbeid en oppervlakte van
luchtcompressor
(Slide 48, Hbp 22)
Extra blad bij slides
c 21 c 22
-
( ) (
ḿ h1 + + p1 v 1 +Q+ Ẃ =ḿ h2 + + p2 v 2
2
´
2 )
Hoofdstuk 2: The working fluid (arbeidsfluidum)
- v = x. vg + (x – 1).vf
- h = x. hg + (x – 1).hf
- u = x. ug + (x – 1).uf
- volume/enthalpie/inwendige
energie van natte stoom in
tweefasig gebied
(Slide 64, Hbp 33)
- Uit h = x. hfg + hf halen we x.
- v = x. vfg + vf
- u = x. ufg + uf
- Dampgehalte/volume/inwendige
energie berekenen
(Slide 64, Hbp 33)
2
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