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WGU STatistics Test QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+ 2025/2026 $12.99   Add to cart

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WGU STatistics Test QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+ 2025/2026

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  • Course
  • WGU C784 APPLIED HEALTHCARE STATISTICS
  • Institution
  • WGU C784 APPLIED HEALTHCARE STATISTICS

WGU STatistics Test QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+ 2025/2026

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  • November 6, 2024
  • 21
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • WGU C784 APPLIED HEALTHCARE STATISTICS
  • WGU C784 APPLIED HEALTHCARE STATISTICS
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Ashley96
WGU STatistics Test

1. A scientific trial designed to assess the efficacy of a brand new drug to increase HDL ldl
cholesterol is performed. One hundred patients sign up in the observe and are
randomized to obtain either a brand new drug or a placebo. A multiple regression
analysis is used to assess effect change. Let T = Treatment (1 = new drug, zero =
placebo), M = male gender (1 = Yes, 0 = No), and TM = the interaction of remedy and
male gender.
2.
3. Given the following effects:
4.
5. Independent variable Regression coefficient T p-value
6. Intercept 39.24 sixty five.89 0.0001
7. T(Treatment) -zero.36 -0.Forty three 0.6711
8. M(Male) -0.18 -0.Thirteen zero.8991
9. TM(Treatment X Male) 6.55 3.37 zero.0011
10. What is the linear regression model?
11. T = 65.89 - zero.Thirteen(M) + three.37(TM)
12. HDL = 39.24 - zero.36(T) - zero.18(M) + 6.Fifty five(TM)
13. T = 65.89 - zero.43(T) - zero.Thirteen(M) + three.37(TM)
14. HDL = 65.89 - zero.43(T) - 0.Thirteen(M) + 3.37(TM)
15. HDL = -0.36(T) - 0.18(M) - ANS-HDL = 39.24 - 0.36(T) - zero.18(M) + 6.Fifty five(TM)
16. A employer wants to rent personnel who're most probable to be successful at promoting
the organization's merchandise. The records analyst needs to decide if intelligence and
friendliness are expecting income performance of contemporary employees. The
cutting-edge employees are given tests to degree each elements, and their sales overall
performance facts is checked, giving the organization 3 rankings for every worker.
17.
18. What is the criterion variable for this study?
19.
20. YOUR
21. ANSWER CORRECT
22. ANSWER
23. Friendliness
24. Intelligence
25. Strategy effects
26. Sales performance - ANS-Sales overall performance
27. A records analyst is doing an evaluation the use of t-exams and gets the subsequent
output:
28.
29. t -stat: 2.Eight

,30. p-value: .006
31. Critical price: 1.2
32.
33. Which end may be drawn?
34. Accept the null hypothesis.
35. The crucial value is too high.
36. Reject the null speculation.
37. The population approach are comparable. - ANS-Reject the null hypothesis
38. A records analyst is examining the relationship with scholar drivers among driving ability
and texting. A using circuit is installation and a collection of students are every tested
twice. The first take a look at is finished whilst sending and receiving texts and the
second take a look at is recorded with out texting. After every of the exams, the number
of cones hit via student drivers is recorded.
39.
40. What are two suitable conclusions that must be made?
41.
42. Choose 2 solutions
43.
44.
45.
46. Dependent variable is non-stop.
47. Independent variable is texting situation.
48. The distribution is skewed.
49. A t-check need to be used. - ANS-Independent variable is texting circumstance.
50. A t-take a look at must be used.
51. A statistics analyst is performing logistic regression on elements with high
multicollinearity.
52.
53. What is an assumption of logistic regression this is being violated?
54.
55. YOUR
56. ANSWER CORRECT
57. ANSWER
58. Normally disbursed variables
59. Variable independence
60. High R 2
61. Categorical facts kind - ANS-Variable independence
62. A records analyst is reading the relationship among gender and marriage the usage of
the result under:
63.
64. T = check: Paired pattern for manner
65. Married Gender
66. Mean zero.Forty eight zero.Sixty four
67. Variance 0.26 0.24

, 68. Observations 25 25
69. Pearson correlation zero.220176
70. Hypothesized suggest distinction zero
71. df 24
72. T stat -1.28103
73. Confidence stage zero.95
74. P (T<=t) one-tail zero.106213
75. t important one-tail 1.710882
76. P (T<=t) two-tail 0.212425
77. t critical two-tail 2.063899
78. Given a confidence level of 95%, what can be concluded?
79.
80. There is no significant difference of mean between these two groups given the t-values.
81. There is a significant difference of mean between these two group as our null hypothesis
is µ 1 - µ 2 = 0.
82. There is a significant difference of mean between these two groups as Pearson
correlation is positive.
83. There is a significant difference of mean between these two group as our alternative
hypothesis is µ 1 > µ 2. - ANS-There is not any full-size difference of mean among these
businesses given the t-values.
84. A statistics analyst is checking out the outcomes of forms of remedy.
85.
86. Given the subsequent effects:
87.
88. Medication 1 Medication 2
89. Cured 58 39
90. Uncured 22 57
91. The analyst performs the chi-rectangular check. What is the expected matter, rounded to
the closest entire wide variety, of uncured that have been given medicine 1?
92.
93. YOUR
94. ANSWER CORRECT
95. ANSWER
96. 26
97. 36
98. 44
99. 53 - ANS-36
100. A records analyst wishes to decide whether or not antioxidants in blackberries can
reduce age-associated cognitive decline. Twenty-5 adults between sixty five and 80 are
selected to devour blackberries for 6 months and be retested. The unique ratings are
compared with the second one scores to decide whether or not there has been decline.
101.
102. What is the appropriate version to test the speculation?
103.

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