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UCF Chemistry IA (CH2040) Exam With Complete Solutions Latest Update
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UCF Chemistry IA (CH2040) Exam With Complete SolutionsLatest Update
UNIT 4
Combustion of Methane:
CH4(g) + 2 02 → C02 (g) + 2 H20 (g)
a) If we have five molecules of CH4 and eight molecules of 02, which is the limiting
reactant? - ANSWER 02 is limiting reactant because it yields the least amount of product
UNIT 4
N2 (g) + 3 H2 (g) → 2 NH3 (g)
Find mol of NH3 (reactant and excess) - ANSWER H2 is the limiting reactant because it
yields 2 molecules of NH3 while N2 yields 6 molecules of NH3
UNIT 4
How many moles of Si3N4 can be made from 1.20 moles of of Si and 1.00 moles of N2 in
the following reaction?
3 Si + 2 N2 -> Si3N4 - ANSWER LOOK IN WEBCOURSES
UNIT 4
Percent Yield Formula: - ANSWER %yield: actual yield/ theoretical yield
UNIT 4
64.0g of methanol, CH3OH, were expected to be produced through the reaction:
C0 (g) + 2 H2 (g) -> CH3OH (l)
One student got 56.0g of methanol, for the reaction in the laboratory. What is the % yield
of methanol? - ANSWER 87.5%
, UNIT 4
Benzene, C6H6, reacts with bromine to form bromobenzene, C6H5Br and hydrogen
bromide. Reaction of 8.00 g benzene with excess bromine yield 12.85g bromobenzene.
Calculate %yield of bromobenzene. - ANSWER 79.9%
UNIT 4
Combustion Reactions: - ANSWER reaction of substance with O2 to form one or more
oxygen containing compounds, often including water.
Compounds containing C & H & O always form C02 and H20 upon complete combustion.
UNIT 4
Alkali Metal Reactions: - ANSWER Involve group 1A from the periodic table ie Li, Na, K,
Rb, Cs, Fr) Reactions of alkali metals and nonmetals are vigorous and form ionic
compounds. React vigorously with water to form dissolved alkali metal ion, the
hydroxide ion and hydrogen gas. product: 2 A metals+ (aq) + 2 0H- (aq) + H2 (aq) Also
react with hydrogen gas.
UNIT 4
Halogen Reactions: - ANSWER Metal halides: halogens react with metals
Hydrogen halides: halogens react with hydrogen
Interhalogen compounds: Halogens react with each other through covalent bond
UNIT 4
Solid ReO3 is a material that is an extremely good conductor of electricity. It can be
formed by chemical reaction:
Re (s) + 3 Re2O7 (s) -> 7 ReO3 (s)
If 3 mol of Re and 3 mol of Re2O7 are allowed to react, 7 mol of ReO3 are produced.
Which of the following statements is the best reason that 7 mol of ReO3 are produced
during the chemical reaction? a) The balanced chemical equation shows that 7 mol of
ReO3 will always be produced regardless of the starting amounts of the reactants.
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